If you have 8.51x10-3 g of O₂, and excess ZnS, moles of ZnO form is 0.174×10⁻³ moles.
The balanced equation is given as :
2ZnS + 3O₂ ------> 2ZnO + 2SO₂
number of moles of O₂ = mass / molar mass
= 8.51 × 10⁻³ g / 31.998 g/mol
= 0.265× 10⁻³ moles
now, 3 moles of O₂ form 2 moles of ZnO
0.265× 10⁻³ moles of O₂ form( 2/3) × 0.265× 10⁻³ = 0.174×10⁻³ moles
The number of moles of ZnO is 0.174×10⁻³ moles
Thus, If you have 8.51x10-3 g of O₂, and excess ZnS, moles of ZnO form is 0.174×10⁻³ moles.
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