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Alexus [3.1K]
2 years ago
7

onsider the structure. a carbon is bonded to two three carbon chains and a branched alkane. the branched alkane is a 2 carbon ch

ain with a methyl on carbon 1. select the correct name for the given structure.
Chemistry
1 answer:
pshichka [43]2 years ago
4 0

If we consider a structure in which a carbon is bonded to two three carbon chains and a branched alkane then the branched alkane is a 2 carbon chain with a  ethyl on Carbon 1 then the correct name of the structure is <u>4-(isopropyl)heptane. </u>

The two three carbon chains bonded to the carbon atom will form the parent chain of this structure and this chain will have 7 carbon atoms in it.

Since this chain is that of an alkane and it has no functional group attached so the root name will be heptane.

Now, we have to add a prefix by naming the branched alkyl chain. The branched chain has 3 carbon atoms in it with a methyl group on carbon 1.

So, this name of this group will be propyl.

The position of this propyl group is 4th on the parent chain so the full name of the structure will be 4-(isopropyl)heptane.

To know more of branched alkane here

brainly.com/question/14507628

#SPJ4

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Given the following equation: 8 Fe + S8 —&gt; 8 FeS what mass of iron is needed to react with 5.65 mol of sulfur S8
Mekhanik [1.2K]

Answer:

2522g

Explanation:

8Fe + S8 —> 8FeS

From the question,

8moles of Fe required 1mole of S8.

Therefore, Xmol of Fe will require 5.65mol of S8 i.e

Xmol of Fe = 8 x 5.65 = 45.2moles

Now we need to covert 45.2moles to gram. This is illustrated below below:

Molar Mass of Fe = 55.8g/mol

Number of mole of Fe = 45.2moles

Mass of Fe =?

Mass = number of mole x molar Mass

Mass of Fe = 45.2 x 55.8

Mass of Fe = 2522g

Therefore, 2522g of Fe is needed for the reaction.

4 0
3 years ago
What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

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