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1 year ago

Find the x-component of this

Physics

2 answers:

Mashcka [7]1 year ago

8 0

The horizontal or x component of the vector is 53.5 m.

<h3>What is the x component?</h3>

We know that a vector quantity must posses both magnitude and direction. In this case, of a vector is inclined at an angle then the vector could have a vertical and a horizontal component. Recall that vector may have have;

- A vertical component

- A horizontal component

Recall that when we resolve a vector, we are able to obtain the effective component of the vector in the given direction. It could be vertical or horizontal.

The horizontal component of the vector is V cos θ where V is the numerical value of the vector.

Thus the horizontal component is;

55.1 m Cos 13.9 = 53.5 m

Learn more about components of a vector:brainly.com/question/4179238

#SPJ1

mash [69]1 year ago

4 0

Answer:

13.24

Explanation:

Fx=Fcos(theta)

but remember theta is measured from the x axis, so in this case it makes theta 76.1 degrees and not 13.9.

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A uniform disk, a thin hoop, and a uniform sphere, all with the same mass and same outer radius, are each free to rotate about a

olga nikolaevna [1]

Answer:

4 hoop, disk, sphere

Explanation:

Because

We are given data that

Hoop, disk, sphere have Same mass and radius

So let

And Initial angular velocity, = 0

The Force on each be F

And Time = t

Also let

Radius of each = r

So let's find the inertia shall we!!

I1 = m r² /2

= 0.5 mr² the his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere wiil be

I3 = (2/5) mr²

= 0.4 mr²

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

So we can see that

ωf is inversely proportional to moment of inertia.

And so we take the

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

hoop, disk, sphere

Option - 4

5 0

3 years ago

How are musical instruments grouped?

rosijanka [135]

A and B are equivalent. That's one way instruments are often grouped. (the "sopranos", the "altos", the "bass")

C is another way instruments are often grouped; (the "woods", the "brass")

D is another way instruments are often grouped; (the "strings", the "percussions")

6 0

3 years ago

Read 2 more answers

An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 m in t

Liono4ka [1.6K]

(a) 5.69 N/C, vertically downward

We can calculate the acceleration of the electron by using the SUVAT equation:

$d=ut+\frac{1}{2}at^2$

where

d = 4.50 m is the distance travelled by the electron

u = 0 is the initial velocity of the electron

$t=3.00 \mu s = 3.0 \cdot 10^{-6} s$ is the time of travelling

a is the acceleration

Solving for a,

$a=\frac{2d}{t^2}=\frac{2(4.50)}{(3.0\cdot 10^{-6})^2}=1.0\cdot 10^{12} m/s^2$

Given the mass of the electron,

$m=9.11\cdot 10^{-31} kg$

We can find the electric force acting on the electron:

$F=ma=(9.11\cdot 10^{-31})(1.0\cdot 10^{12})=9.11\cdot 10^{-19}N$

And the electric force can be written as

$F=qE$

where

$q=-1.6\cdot 10^{-19}C$ is the charge of the electron

E is the magnitude of the electric field

Solving for E,

$E=\frac{F}{q}=\frac{9.11\cdot 10^{-19}}{-1.6\cdot 10^{-19}}=-5.69 N/C$

The negative sign means that the direction of the electric field is opposite to the direction of the force (because the charge is negative): since the force has same direction of the acceleration (vertically upward), the electric field must point vertically downward.

(b) Yes

We can answer the question by calculating the magnitude of the gravitational force acting on the electron, to check if it is relevant or not. The gravitational force on the electron is:

$F=mg$

where

$m=9.11\cdot 10^{-31} kg$ is the mass of the electron

$g=9.81 m/s^2$ is the acceleration due to gravity

Substituting,

$F=(9.11\cdot 10^{-31})(9.81)=8.93\cdot 10^{-30}N$

We see that the gravitational force is basically negligible compared to the electric force calculated in part (a), therefore we can say it is justified to ignore the effect of gravity in the problem.

7 0

4 years ago

A special device can transmit sound that is out of phase with the sound of a noisy jackhammer to the jackhammer operator by mean

goldenfox [79]

Answer:

, l l. l

Explanation:

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3 years ago

In chemistry, potential energy is usually considered to be the energy _____________.

Lunna [17]

Answer:

The answer is option D. Stored in the chemical bonds.

Hope it helps............

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3 years ago