Question

You have a concave mirror with a focal length of 100.0 cm, and you want an image that is upright and 10.0 times as tall as the object. Where should you place the object?Select one:a.9.09 cmb.12.09 cmc.7.12 cmd.5.8 cm

Answer 1

ANSWER:

a. 9.09cm

STEP-BY-STEP EXPLANATION:

Given:

Focal length = 100 cm

Distance image = -10 cm

We use the following formula to calculate the value of the distance of the object:

$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$

We substitute each value and calculate the distance of the object just like this:

$\begin{gathered} \frac{1}{d_o}+\frac{1}{-10}=\frac{1}{100} \\ \\ \frac{1}{d_{o}}=\frac{1}{100}+\frac{1}{10} \\ \\ \frac{1}{d_o}=\frac{11}{100} \\ \\ d_o=\frac{100}{11} \\ \\ d_o=9.09\text{ cm} \end{gathered}$

Therefore, the correct answer is option a. 9.09cm