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Dvinal [7]
2 years ago
9

a student solving a physics problem to find the unknown has applied physics principles and obtained the expression: μkmgcosθ

Physics
1 answer:
KonstantinChe [14]2 years ago
5 0

The physics problem to find the unknown has applied physics principles will be the following:

The simplified expression for coefficient of kinetic friction is 0.097.

The given parameters:

g = 9.8 m/s²

a = 3.6 m/s²

θ=27.0∘

The simplified expression for coefficient of kinetic friction is calculated as follows;

μkmgcosθ = mgsinθ − ma

m(μkgcosθ) = m(gsinθ − a)

μkgcosθ = gsinθ − a

The practise of using physics as a science to assist people and address their issues is known as applied physics.

Engineering is distinct from it since engineers deal with clearly defined problems. Applying physics to the development of new technologies or the resolution of engineering issues is the work of applied physicists.

Learn more about physics:

brainly.com/question/24517831

#SPJ4

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Answer:

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(1)

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

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From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

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From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making t the subject we have

t=\frac {v-u}{a}

Substituting u=0m/s since at rest, v=15m/s and a=5 \frac {m}{s^{2}}

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When initial and final velocity are constant, there’s no acceleration as proven below

From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making a the subject we have

a=\frac {v-u}{t}

Substituting u=20 since it’s at rest, v=20m/s and t=10 seconds

a = \frac {20-20}{10}=0 m/s^{2}

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From v= u + at where v is final velocity, u is initial velocity, a is acceleration and t is time.

Making t the subject we have

t=\frac {v-u}{a}

Substituting u=9m/s since at rest, v=0m/s and a=-4.1 \frac {m}{s^{2}}

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Answer:

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