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nevsk [136]
1 year ago
11

answer yes if the substance becomes part of the filtrate or answer no if the molecule does not become part of the filtrate

Chemistry
1 answer:
SVETLANKA909090 [29]1 year ago
4 0

Yes, the substance becomes the part of filtrate. No, the molecule does not become part of the filtrate.

<h2>What is filtrate?</h2>

The most common example is making tea. While preparing tea, a filter or a sieve is used to separate tea leaves from the water. Through the sieve pores, only water will pass. The liquid which has obtained after filtration is called the filtrate; in this case, water is the filtrate.

<h3>Which substance becomes the part of the filtrate?</h3>

The substances that are normally found in the filtrate  are plasma components (such as water, nutrients, dissolved gases, electrolytes, and metabolic wastes) excluding plasma proteins and blood cells.

<h3>Why molecule becomes the part of the filtrate?</h3>

Proteins are large molecules that cannot pass the wall of capillaries during  filtration, hence, this molecule is not normally part of the  filtrate.

Know more about filtrate visit the link

brainly.com/question/23945157

#SPJ4

<h3 />

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What is the part of the cartridge that actually flies outward (the projectile)?
zhannawk [14.2K]

Answer:

the culotte, the fulminant capsule and the sheath or cap together with remains of powder

Explanation:

A bullet has a nose, sheath or casing, a short propellant charge, and a capsule.

All these components are part of the vouchers. The classification of these is in metallic and semi-metallic.

3 0
2 years ago
Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia, where hydroele
weeeeeb [17]

If the coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

(a) The reaction is

2H₂O + 2e⁻ → H₂ + 2OH⁻

According to the reaction, 2 moles of electrons flow per mole of reaction,

(b) Given

T = 25°C

Change Celsius into Kelvin

T = 25°C

   = (25 + 273 ) K

   = 298 K

<h3>What is Ideal Gas Law ?</h3>

It is expressed as

PV = nRT

Hence ,

n = \frac{PV}{RT}

   = \frac{(12)(3.5.10^{6} )}{(0.082057)(298)}

   = 1.7176 ×10⁶ mole

Now, From the given reaction we can say that ,1 mole of H₂  is produced by 2 moles of electron

Hence, 1.7176 × 10⁶ mole of H₂ is produced by

= 2 × 1.7176 × 10⁶ moles of  electron

= 3.435 ×10⁶ moles of electron

We know that

charge = moles of electron × F

          =  (3.435 ×10⁶ × 96500) C

           =  3.31 × 10¹¹ C

(c) We know that,

Voltage = \frac{energy}{charge}  =  \frac{J}{C}

1.44 V = \frac{energy}{3.31 . 10^{11} }

Energy = 1.44 V × 3.31 × 10¹¹ C

            =  4.766 × 10¹¹ Joules

Thus from the above conclusion we can say that, coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

Learn more about Fuel Cell here : brainly.com/question/16612142

#SPJ4

Disclaimer : The question given was incomplete on portal, Here is the complete question.

Question : Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia countries, where hydroelectric plants produce inexpensive electric power, the H₂ can be made industrially by the electrolysis of water.

a) How many moles of electrons flow per mole of reaction ?

b) How many coulombs are needed to produce 3.53X10⁶ L of H₂ gas at   12.0 atm and 25°C.

c) If the coulombs are supplied at 1.44 V, how many joules are produced?

8 0
1 year ago
If greenhouse gases in the atmosphere act like a blanket around the Earth, how is this "blanket” being changed by human activiti
Afina-wow [57]
The gases we create are adding to that blanket making sun light harder to escape,so the world heats up due to this addition to the layer 
4 0
3 years ago
Read 2 more answers
The ratio of x to y is 4 to 12. Fill in numbers to<br>form a table with the given ratio,​
murzikaleks [220]

Answer:

Explanation:

x                                     y

4                                     12

8                                     24

12                                   36

16                                   48

20                                  60

           

4 0
3 years ago
A 36.2 g object has a heat capacity of 12.5 J/ oC. How much energy (in J) is required to raise the temperature by 5.73 oC?
iren2701 [21]

Answer:

\Delta H=2592.825\ J

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of object = 36.2 g

Specific heat = 12.5 J/g°C

\Delta T=5.73\ ^0C

So,  

\Delta H=36.2\times 12.5\times 5.73\ J=2592.825\ J

\Delta H=2592.825\ J

7 0
2 years ago
Read 2 more answers
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