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kodGreya [7K]
4 years ago
5

12) If you are travelling at 0.75c how fast are you moving? (3 points)

Physics
1 answer:
Roman55 [17]4 years ago
4 0

Answer:

Explanation:

Speed of light (c) is 299792458m/s in vacuum. If you move at 0.75c your speed will be

v=0,75x300000000

approximately v= 225000000m/s

  v= 2,25x10⁶m/s

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A construction worker is carrying a load of 40 kg over his head and is walking at a constant velocity if he travels a distance o
Anastasy [175]

Answer:

W = 0

Explanation:

We are given with, a construction worker is carrying a load of 40 kg over his head and is walking at a constant velocity. He travels a distance of 50 m.

The work done by an object is given by :

W=Fd

F = ma

So,

W=mad

m is mass

a is acceleration

d is displacement

The worker is moving with constant velocity, its acceleration will be 0. So, the work done by the worker is 0.

8 0
4 years ago
A deuteron particle consists of one proton and one neutron and has a mass of 3.34x10^-27 kg. A deuteron particle moving horizont
nikklg [1K]

_dThe radius of curvature of a subatomic particle under a magnetic field is given by the following formula:

r=\frac{mv}{qB}

Where:

\begin{gathered} r=\text{ radius} \\ v=\text{ velocity} \\ q=\text{ charge} \\ B=\text{ magnetic field} \end{gathered}

We can determine the quotient between the velocity and the charge of the deuteron particle from the formula. First, we divide both sides by the mass:

\frac{r_d}{m_d}=\frac{v}{q_B_}

Now, we multiply both sides by the magnetic field "B":

\frac{Br_d}{m_d}=\frac{v}{q}

Since the charge of the deuterion is the same as the charge of the proton and the velocity we are considering are the same this means that the quotient between velocity and charge is the same for both particles. Therefore, we can apply the formula for the radius again, this time for the proton:

r_p=\frac{m_pv}{qB}

And substitute the quotient between velocity and charge:

r_p=\frac{m_p}{B}(\frac{Br_d}{m_d})

Now, we cancel out the magnetic field:

r_p=\frac{m_pr_d}{m_d}

Now, we substitute the values:

r_p=\frac{(1.67\times10^{-27}kg)(0.385m)}{(3.34\times10^{-27}kg)}

Solving the operations:

r_p=0.193m=19.3cm

Therefore, the radius is 19.3 cm.

3 0
2 years ago
How do you think the liquid density affects the buoyancy of objects placed in the liquid?
Brums [2.3K]

Answer:

density can be written as:

d = F / V  (weight density) or M / V (mass density)

Since F in the first equation can be written as

B = d V where B is the buoyant force and is proportional to the

weight of the liquid displaced

For a given volume the weight of the liquid displaced is proportional to the density and hence the buoyant force

7 0
3 years ago
How does acceleration values differ mathematically from deceleration values?
Serggg [28]
If a problem says the acceleration is some positive value than solve using that value, a negative acceleration is said to be deceleration. E.g. a car decelerating at 10 m/sec can be said to be accelerating at -10 m/sec.

If a problem states decelerates at A, then use -A for acceleration in the classic equations which are for acceleration. If a problem says accelerates at a negative value like -A the use -A as the value for acceleration, it can also be said to be decelerating at A.
8 0
4 years ago
Problem: At the local swimming hole, a favorite trick is torun
denis23 [38]

Answer:

2 revolutions

Explanation:

Assume that when she runs off the edge of the 8.3m high cliff, her vertical speed is 0. So gravitational acceleration g = 9.8m/s2 is the only thing that makes her fall down. So we can use the following equation of motion to calculate the time it takes for her to fall down:

s = gt^2/2

where s = 8.3 m is the distance that she falls, t is the time it takes to fall, which is what we are looking for

t^2 = \frac{2s}{g} = \frac{2*8.3}{9.8} = 1.694

t = \sqrt{1.694} = 1.3 s

Since she rotates with an average angular speed of 1.6rev/s. The number of revolutions she would make within 1.3s is

rev = 1.3 * 1.6 = 2 revolution

8 0
4 years ago
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