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blagie [28]
1 year ago
5

Explain in your own words the interplay of temperature (heat) and intermolecular forces and the effect of these two variables on

any particular substance achieving the three common states of matter.
Chemistry
1 answer:
DochEvi [55]1 year ago
7 0

The forces between particles are called intermolecular forces. A strong intermolecular force means that the particles are tightly paced and is associated with the solid phase. Moderate intermolecular force is associated with the liquid state and little to no intermolecular force is associated with the gaseous state. Temperature has a direct effect on the state of matter in which the substance exists has. Generally speaking, a rise in tempreature changes a substance from the solid to liquid phase and from liquid to gaseus phase. The reverse is true, if the temperature lowers then the substance will go from gas to liquid and liquid to solid. It is important to not that temperature affects intermolecular forces. As the temperature increases then the individual particles become excited and gain enough energy to over the intermolecular forces and so the particles seperate from each other.

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Why do we use a double arrow in the dissociation equation for a weak acid answer?
Zepler [3.9K]
Answer is: because weak acids do not dissociate completely.

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Strong acids completely ionize in water and give large amount ofhydrogen ions (H</span>⁺), so we use only one arrow, because reaction goes in one direction and there no molecules of acid in solution.

For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).

<span> Weak acid partially ionize in water and give only a few hydrogen ions (H</span>⁺), in the solution there molecules of acid and ions.

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4 0
3 years ago
hi, can you check if my answers are correct? I'm not so confident in this topic (topic: Classifying Types of Chemical Reactions)
NikAS [45]
I am pretty sure your answer are correct , from what I know. Good job!
7 0
3 years ago
Plsss helpppp<br> im confused<br> will mark BRAINLIEST
mr_godi [17]
I am thinking Li & CI :)
6 0
3 years ago
Read 2 more answers
Which of the following hypotheses cannot be tested using the scientific method
Arturiano [62]
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
7 0
3 years ago
Read 2 more answers
When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
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