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1 year ago

The blank is an estimating technique which requires knowledge and experience

Physics

1 answer:

I am Lyosha [343]1 year ago

4 0

The ratio method exists as an estimating technique which requires knowledge and experience,

<h3>What is meant by ratio method?</h3>

Ratio technique: This method uses a basic project attribute, like size in square meters or the number of software features, and the cost per meter or feature to project the overall cost and length of the project.
Ratio analysis in project management can measure how effectively resources are being managed and how efficiently the project is running. The balance sheet and income statement of an organization are typically where financial ratios in the corporate environment are derived.
A measure of the relationship between a proposed project's relative costs and benefits, expressed in monetary or qualitative terms, is the benefit-cost ratio (BCR). The expectation is that a project with a BCR of greater than 1.0 will provide a firm and its investors with a positive net present value.

Hence, The ratio method exists as an estimating technique which requires knowledge and experience,

To learn more about ratio method refer to:

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A spherical capacitor contains a charge of 3.00 nC when connected to a potential difference of 230 V. If its plates are separate

Assoli18 [71]

Answer:

Part(a): the capacitance is 0.013 nF.

Part(b): the radius of the inner sphere is 3.1 cm.

Part(c): the electric field just outside the surface of inner sphere is $\bf{2.81 \times 10^{4}~n~C^{-1}}$ .

Explanation:

We know that if 'a' and 'b' are the inner and outer radii of the shell respectively, 'Q' is the total charge contains by the capacitor subjected to a potential difference of 'V' and ' $\epsilon_{0}$ ' be the permittivity of free space, then the capacitance (C) of the spherical shell can be written as

$C = \dfrac{4 \pi \epsilon_{0}}{(\dfrac{1}{a} - \dfrac{1}{b})}~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

Part(a):

Given, charge contained by the capacitor Q = 3.00 nC and potential to which it is subjected to is V = 230V.

So the capacitance (C) of the shell is

$C &=& \dfrac{Q}{V} = \dfrac{3 \times 10^{-90}~C}{230~V} = 1.3 \times 10^{-11}~F = 0.013~nF$

Part(b):

Given the inner radius of the outer shell b = 4.3 cm = 0.043 m. Therefore, from equation (1), rearranging the terms,

$&& \dfrac{1}{a} = \dfrac{1}{b} + \dfrac{1}{C/4 \pi \epsilon_{0}} = \dfrac{1}{0.043} + \dfrac{1}{1.3 \times 10^{-11} \times 9 \times 10^{9}} = 31.79\\&or,& a = \dfrac{1}{31.79}~m = 0.031~m = 3.1~cm$

Part(c):

If we apply Gauss' law of electrostatics, then

$&& E~4 \pi a^{2} = \dfrac{Q}{\epsilon_{0}}\\&or,& E = \dfrac{Q}{4 \pi \epsilon_{0}a^{2}}\\&or,& E = \dfrac{3 \times 10^{-9} \times 9 \times 10^{9}}{0.031^{2}}~N~C^{-1}\\&or,& E = 2.81 \times 10^{4}~N~C^{-1}$

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3 years ago

Which of the following is a TRUE

DENIUS [597]

The statement that is the most true regarding the states of matter is the first statement.

A. Most matter on Earth exists as a solid, liquid, or gas.

This is correct since most of the matter on Earth exists in those 3 states, meanwhile plasma is not a state that most of matter on earth is found in since it is mostly associated to stars and the external galactic regions.

Therefore, B is incorrect.

C is false, since almost of all of the matter on earth can transform and change through each of the 3 states of matter, solid, liquid, and gas.

D is false since most of the matter in universe is actually made out of plasma instead of a liquid. In fact, over 99% of the known universe's matter is said to consist of plasma.

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trasher [3.6K]

Answer:

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Dahasolnce [82]

Answer:

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If an electromagnetic wave has components Ey = E0 sin(kx - ωt) and Bz = B0 sin(kx - ωt), in what direction is it traveling?

fomenos

Answer:

Its traveling in the +x direction

Explanation:

The E-field is in the +y-direction, and the B-field is in the +z-direction, so it must be moving along the +x-direction, since the E-field, B-field and the direction of moving are all at right angles to each other.

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3 years ago