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Ipatiy [6.2K]
3 years ago
12

A father is pulling his child on a sled in the snow. According to Newton’s Third Law, the force the father exerts on the sled is

equal to the force the sled exerts on the father but opposite in direction. How is it possible that the father can pull the child and sled forward?
Physics
1 answer:
viktelen [127]3 years ago
5 0
That is because there are other forces like the friction forces that apply differently on both of them. The frictional forces applied to the sled are smaller than they are on the father, for example, so it's possible for him to pull it.
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Akio draws the ray diagram shown.
Inessa [10]

Answer: Move the small car so it appears on the left side of the lens.

Explanation:

Because the lens is reflective the small car would apear on the same side as the normal car.

Hope this helps :)

3 0
3 years ago
The Hall effect can be used to calculate the charge-carrier number density in a conductor. A conductor carrying current of 2.0 A
marysya [2.9K]

Answer:

option D

Explanation:

given,

A conductor is carrying current = 2.0 A is 0.5 mm thick

Hall voltage = 4.5 x 10-6 V

uniform magnetic field  =  1.2 T

density of the charge = n =?

hall voltage =V_h =\dfrac{i\ B}{n\ e\ L}

n = \dfrac{i\ B}{V\ e\ L}

n = \dfrac{2 \times 1.2 }{4.5 \times 10^{-6}\times 1.6 \times 10^{-19} \times 0.5 \times 10^{-3}}

n = 6.67 × 10²⁷ charges/m

hence the correct answer is option D

7 0
3 years ago
A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span o
wariber [46]

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

<h3>What is power?</h3>

In physics, power (P) is the work (W) done over a period of time.

  • Step 1. Calculate the work done by the bodybuilder each time.

The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.

W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N

  • Step 2. Calculate the work done by the bodybuilder over 10 times.

W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N

  • Step 3. Calculate the power exerted by the bodybuilder.

The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.

P = 1.9 × 10⁴ N/45 s = 421 W

A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)

Learn more about power here: brainly.com/question/911620

#SPJ1

4 0
2 years ago
Although planets orbit the Sun in ellipses, all the planetary orbits are fairly close to circular and not very eccentric.
Nutka1998 [239]

Answer:

False

Explanation:

The Sun rotates in this same, right-hand-rule direction. All planetary orbits lie in nearly the same plane. All planetary orbits are nearly circular (eccentricity near zero).

Rate as Brainliest please

8 0
3 years ago
Anyone who scuba dives is advised not to fly within the next 24 h because the air mixture for diving can introduce nitrogen into
Katyanochek1 [597]

Answer:

Explanation:

Let pressure at surface of earth be P Pa.  

pressure at height of 8.1 km in air can be calculated as follows .

pressure due to column of air of 8.1 km height

= h d g , h is height , d is density of air and g is acceleration due to gravity

= 8.1 x 1000 x .87 x 9.8 = 6.9 x 10⁴ Pa .

pressure at the height of 8.1 km

= P - 6.9 x 10⁴ Pa

Pressure due to  column  of 16 m in the sea

= h d g

16 x 1000 x 9.8

= 15.68 x 10⁴ Pa .

Pressure at depth of 16m

= P + 15.68 x 10⁴

pressure difference between points at height of 8.1 km and pressure at point 16 m deep

=  P + 15.68 x 10⁴ -  P +  6.9 x 10⁴ Pa

= 22.58 x 10⁴ Pa .

3 0
4 years ago
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