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lesya [120]
2 years ago
8

question how does the gravitational field gx at the surface of planet x compare with the gravitational field gy at the surface o

f planet y?
Physics
1 answer:
siniylev [52]2 years ago
8 0

The  gravitational field gx at the surface of planet x  (M/m)(r/R)² times the gravitational field gy at the surface of planet y.

<h3>What is gravitational field?</h3>

A gravitational field, as defined by physics, is the influence a massive body has on the area surrounding it, exerting a force on another huge body. In other words, a gravitational field, which is measured in newtons per kilograms (N/kg), aids in the explanation of gravitational field.

Now, Let planet x has mass M and radius R:  then gravitational field at the surface of planet: gₓ = GM/R².

Let planet y has mass m and radius r:  then gravitational field at the surface of planet: g_y = Gm/r².

Hence, gₓ/g_y = (M/m)(r/R)².

So, the  gravitational field gx at the surface of planet x  (M/m)(r/R)² times the gravitational field gy at the surface of planet y.

Learn more about gravitational field here:

brainly.com/question/12324569

#SPJ1

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Answer:

For Potassium:

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Frequency = 4.3 x 0¹⁴ Hz

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Explanation:

Wavelength is represented by λ, and Frequency is represented by ν .

E (energy) = hν = hc/λ,  where ν = frequency; c = speed of light = 3 x 10⁸ m/s; 1 s-1 = 1 Hz

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1. Potassium λ (wavelength) = 400 nm, Frequency, ν  is given by :

ν = c/λ = (3 x 10⁸  m/s) / 400 nm

  = (3 x 10⁸ m/s) / 400 x 10⁻⁹ s-1

  = 0.0075 x 10¹⁷s-1

  = 7.5 x 10¹⁴  s-1

Frequency = 7.5 x 10¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (7.5 x 10¹⁴s-1)

E (energy) = 8.83 x 10⁻²¹ J

2. Strontium λ (wavelength) = 700 nm ,Frequency, ν  is given by :

ν = c/λ = (3 x 10⁸ m/s) / 700 nm

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  = 0.00428571428 x 10¹⁷s-1

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Frequency = 4.3 x 0¹⁴ Hz

E (energy) = hν = (6.62 x 10⁻³⁴ J.s) x (4.3 x 0¹⁴s-1)

E (energy) = 2.85 x 10⁻¹⁹ J

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