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il63 [147K]
1 year ago
8

How do I balance these equations? Please explain so I can learn how.

Chemistry
1 answer:
labwork [276]1 year ago
3 0

One mole of CS₂ and two moles of H₂S are formed as products and 3 moles of CH₄ are leftover.

<h3>What is the limiting reagent?</h3>

A limiting reagent is a reactant that is fully exhausted from the reaction mixture at the completion of a  reaction. The limiting reactant will decide the maximum amount of product.

Given, a balanced chemical equation of the reaction between methane and sulphur is:

CH_4 + 4S\longrightarrow CS_2 +2H_2S

Given, the number of moles of the sulphur = 4

The number of moles of methane = 4

From the chemical reaction, one mole of methane reacts with four moles of sulphur. Therefore, four moles of sulphur fully react with one mole of methane and three moles of methane leftover.

Learn more about limiting reagents, here:

brainly.com/question/26905271

#SPJ1

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Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon
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Answer:

C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)

Explanation:

Propane can be turned into hydrogen by the two-step reforming process.

In the first step, propane and water react to form carbon monoxide and hydrogen. The balanced chemical equation is:

C₃H₈(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g)

In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide. The balanced chemical equation is:

CO(g) + H₂O(g) ⇒ H₂(g) + CO₂(g)

In order to get the net chemical equation for the overall process, we have to multiply the second step by 3 and add it to the first step. Then, we cancel what is repeated.

C₃H₈(g) + 3 H₂O(g) + 3 CO(g) + 3 H₂O(g) ⇒ 3 CO(g) + 7 H₂(g) + 3 H₂(g) + 3 CO₂(g)

C₃H₈(g) + 6 H₂O(g) ⇒ + 10 H₂(g) + 3 CO₂(g)

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