Explain the relationship between resistance and the velocity of shortening.

1 answer:

7 0

The velocity of shortening refers to the speed of the contraction from the muscle shortening while lifting a load. The relationship between the resistance and velocity of shortening is inverse. The greater the resistance, the shorter the velocity of shortening and the smaller the resistance, the larger the velocity of shortening.

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When a pendulum with a period of 2.00000 s is moved to a new location from one where the acceleration due to gravity was 9.80 m/

Fynjy0 [20]

1. By 0.02 m/s^2

The period of a pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the gravitational acceleration

Initially, we know:

T = 2.00000 s is the period of the pendulum

g = 9.80 m/s^2 is the acceleration due to gravity at the original location

We can solve the equation for L in order to find the length of the pendulum:

$L=\frac{T^2}{(2 \pi)^2}g=\frac{(2.0000 s)^2}{(2 \pi)^2}(9.80 m/s^2)=0.99396 m$

The length of the pendulum does not change when it is moved to the new location, so we can use the same equation with $T=1.99824 s$ (the new period) and solving it for g to find the acceleration due to gravity at the new location:

$g=L\frac{(2 \pi)^2}{T^2}=(0.99396 m)\frac{(2 \pi)^2}{(1.99824 s)^2})=9.82 m/s^2$

So, the change in gravitational acceleration is

$\Delta g = g_2 - g_1 = 9.82 m/s^2-9.80 m/s^2 = 0.02 m/s^2$

2) the period of the pendulum is directly proportional to the square root of the length, L, and inversely proportional to the square root of the gravitational acceleration, g.

The period of a pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the gravitational acceleration

So, we see that the period of the pendulum is directly proportional to the square root of the length, L, and inversely proportional to the square root of the gravitational acceleration, g.

3) The length of the pendulum does not change

The length of the pendulum does not depend on the location: in fact, only the value of the gravitational acceleration, g, depends on the location, therefore the length of the pendulum, L, does not change.

8 0

3 years ago

What can you conclude about the total mechanical energy of a pendulum as it swings back and forth?

Alchen [17]

Answer:

The total mechanical energy of a pendulum is conserved neglecting the friction.

Explanation:

When a simple pendulum swings back and forth, it has some energy associated with its motion.
The total energy of a simple pendulum in harmonic motion at any instant of time is equal to the sum of the potential and kinetic energy.
The potential energy of the simple pendulum is given by P.E = mgh
The kinetic energy of the simple pendulum is given by, K.E = 1/2mv²
When the pendulum swings to one end, its velocity equals zero temporarily where the potential energy becomes maximum.
When the pendulum reaches the vertical line, its velocity and kinetic energy become maximum.
Hence, the total mechanical energy of a pendulum as it swings back and forth is conserved neglecting the resistance.