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Katen [24]
9 months ago
14

1. What did observations between 1912 and 1917 show?_____

Engineering
1 answer:
valentinak56 [21]9 months ago
7 0

The following set of prompts is astronomy related.

1) It is to be noted that the observations between 1912 and 1917  revealed that the earth was millions of years old and cooled down from a once molten state.

2) Lemaitres argued that the physical world began as a single particle—the "primeval atom," as he termed it—that disintegrated in an explosion, resulting in space and time and the cosmos' ongoing expansion.

3) It is TRUE to state that between 1912 and 1922, astronomer Vesto Slipher at the Lowell Observatory in Arizona uncovered that the spectra of light from many of these celestial entities were systematically shifted to longer wavelengths, or redshifted. The objects referenced here were galaxies in the distance.

4)  The important discovery that Hubble and his assistant discovered about galaxies was that some nebulae were galaxies <u>expanding </u>beyond our own galaxies.

5) It means that the universe has been growing or expanding ever since the Big Bang.

6) By observing very distant objects, scientists can tell whether or not the universe is moving, growing, or shrinking. This concept is referred to as redshift.

7) In 1965, the American Radio Astronomers Arno Penzias and Robert Wilson inadvertently discovered Cosmic Microwave Background Radiation.

8) According to all recent observations and studies, the Universe has no center.

9) It is estimated the Universe is 13.8 Billion Years old.

10) According to the Big Bang Theory, the whole Universe existed within a bubble millions of times smaller than the size of a pinhead. It was hotter and denser than we could have imagined. Then it burst into flames. According to this belief, this explosion produced life as we know it. It should be highlighted that, while the hypothesis has been utilized to explain numerous scientific facts, it is still an unproven theory.

<h3>When did the study of astronomy begin?</h3>

The Assyro-Babylonians made the earliest written records of regular astronomical observations approximately 1000 BCE. Astronomers had built an extensive knowledge of the celestial bodies and documented their periodic movements in Mesopotamia, which is located in the southern section of modern-day Iraq.

Astronomy is the oldest natural science, dating back to antiquity, with roots in prehistoric religious, mythical, cosmological, calendrical, and astrological beliefs and practices: vestiges of these can still be found in astrology, a discipline long intertwined with public and governmental astronomy.

Learn more about astronomy:
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it is not possible to place the wires in the condui

Explanation:

given data

total area = 2.04 square inches

wires total area = 0.93 square inches

maximum fill conduit =  40%

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Can it is possible place wire in conduit conduit

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we know maximum fill is 40%

so here first we get total area of conduit that will be

total area of conduit = 40% × 2.04

total area of conduit = 0.816 square inches

but this area is less than required area of wire that is 0.93 square inches

so we can say it is not possible to place the wires in the conduit

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A medium-sized jet has a 3.8-mm-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to th
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Answer:

F_{thrust} ≅ 111 KN

Explanation:

Given that;

A medium-sized jet has a 3.8-mm-diameter i.e diameter (d) = 3.8

mass = 85,000 kg

drag co-efficient (C) = 0.37

(velocity (v)= 230 m/s

density (ρ) = 1.0 kg/m³

To calculate the thrust; we need to determine the relation of the drag force; which is given as:

F_{drag} = \frac{1}{2} × CρAv²

where;

ρ = density of air wind.

C = drag co-efficient

A = Area of the jet

v = velocity of the jet

From the question, we can deduce that the jet is in motion with a constant speed; as such: the net force acting on the jet in the air = 0

SO, F_{drag}-F_{thrust} = 0

We can as well say:

F_{drag}= F_{thrust}

We can now replace F_{thrust} with F_{drag} in the above equation.

Therefore, F_{thrust} = \frac{1}{2} × CρAv²

The A which stands as the area of the jet is given by the formula:

A=\frac{\pi d^2}{4}

We can now have a new equation after substituting our A into the previous equation as:

F_{thrust} = \frac{1}{2} × Cρ (\frac{\pi d^2}{4})v^2

Substituting our data from above; we have:

F_{thrust} = \frac{1}{2} × (0.37)(1.0kg/m^3)(\frac{\pi(3.8m)^2 }{4})(230m/s)^2

F_{thrust} = \frac{1}{8}   (0.37)(1.0kg/m^3)({\pi(3.8m)^2 })(230m/s)^2

F_{thrust} = 110,990N

F_{thrust}  in N (newton) to KN (kilo-newton) will be:

F_{thrust} = (110,990N)*\frac{1KN}{1,000N}

F_{thrust} = 110.990 KN

F_{thrust} ≅ 111 KN

In conclusion, the jet engine needed to provide 111 KN thrust in order to cruise at 230 m/s at an altitude where the air density is 1.0 kg/m³.

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