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Katen [24]
1 year ago
14

1. What did observations between 1912 and 1917 show?_____

Engineering
1 answer:
valentinak56 [21]1 year ago
7 0

The following set of prompts is astronomy related.

1) It is to be noted that the observations between 1912 and 1917  revealed that the earth was millions of years old and cooled down from a once molten state.

2) Lemaitres argued that the physical world began as a single particle—the "primeval atom," as he termed it—that disintegrated in an explosion, resulting in space and time and the cosmos' ongoing expansion.

3) It is TRUE to state that between 1912 and 1922, astronomer Vesto Slipher at the Lowell Observatory in Arizona uncovered that the spectra of light from many of these celestial entities were systematically shifted to longer wavelengths, or redshifted. The objects referenced here were galaxies in the distance.

4)  The important discovery that Hubble and his assistant discovered about galaxies was that some nebulae were galaxies <u>expanding </u>beyond our own galaxies.

5) It means that the universe has been growing or expanding ever since the Big Bang.

6) By observing very distant objects, scientists can tell whether or not the universe is moving, growing, or shrinking. This concept is referred to as redshift.

7) In 1965, the American Radio Astronomers Arno Penzias and Robert Wilson inadvertently discovered Cosmic Microwave Background Radiation.

8) According to all recent observations and studies, the Universe has no center.

9) It is estimated the Universe is 13.8 Billion Years old.

10) According to the Big Bang Theory, the whole Universe existed within a bubble millions of times smaller than the size of a pinhead. It was hotter and denser than we could have imagined. Then it burst into flames. According to this belief, this explosion produced life as we know it. It should be highlighted that, while the hypothesis has been utilized to explain numerous scientific facts, it is still an unproven theory.

<h3>When did the study of astronomy begin?</h3>

The Assyro-Babylonians made the earliest written records of regular astronomical observations approximately 1000 BCE. Astronomers had built an extensive knowledge of the celestial bodies and documented their periodic movements in Mesopotamia, which is located in the southern section of modern-day Iraq.

Astronomy is the oldest natural science, dating back to antiquity, with roots in prehistoric religious, mythical, cosmological, calendrical, and astrological beliefs and practices: vestiges of these can still be found in astrology, a discipline long intertwined with public and governmental astronomy.

Learn more about astronomy:
brainly.com/question/14375304
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The equilibrium fraction of lattice sites that are vacant in electrum (a silver gold alloy) at 300K C is 9.93 x 10-8. There are
IrinaK [193]

Answer:

the density of the electrum is 14.30 g/cm³

Explanation:

Given that:

The equilibrium fraction of lattice sites that are vacant in electrum  = 9.93*10^{-8}

Number of vacant atoms = 5.854 * 10^{15} \ vacancies/cm^3

the atomic mass of the electrum = 146.08 g/mol

Avogadro's number = 6.022*10^{23

The Number of vacant atoms = Fraction of lattice sites × Total number of sites(N)

5.854*10^{15} = 9.93*10^{-8}  × Total number of sites(N)

Total number of sites (N) = \dfrac{5.854*10^{15}}{9.93*10^{-8}}

Total number of sites (N) = 5.895*10^{22}

From the expression of the total number of sites; we can determine the density of the electrum;

N = \dfrac{N_A \rho _{electrum}}{A_{electrum}}

where ;

N_A = Avogadro's Number

\rho_{electrum} = density of the electrum

A_{electrum} = Atomic mass

5.895*10^{22} = \dfrac{6.022*10^{23}* \rho _{electrum}}{146.08}

5.895*10^{22} *146.08}= 6.022*10^{23}* \rho _{electrum}

8.611416*10^{24}= 6.022*10^{23}* \rho _{electrum}

\rho _{electrum}=\dfrac{8.611416*10^{24}}{6.022*10^{23}}}

\mathbf{  \rho _{electrum}=14.30 \ g/cm^3}

Thus; the density of the electrum is 14.30 g/cm³

7 0
3 years ago
Madison how do you do this
Pani-rosa [81]

Answer:

Do what

Explanation:

Nothing is there

8 0
3 years ago
Read 2 more answers
an electric circuit includes a voltage source and two resistances (50 and 75) in parallel. determine the voltage source required
ASHA 777 [7]

Answer:

The voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.

Explanation:

Given;

Resistance, R₁ = 50Ω

Resistance, R₂ = 75Ω

Total resistance, R = (R₁R₂)/(R₁ + R₂)

Total resistance, R = (50 x 75)/(125)

Total resistance, R = 30 Ω

According to ohms law, sum of current in a parallel circuit is given as

I = I₁ + I₂

I = \frac{V}{R_1} + \frac{V}{R_2}

Voltage across each resistor is the same

1.6 = \frac{V}{R_2}  

V = 1.6 x R₂

V = 1.6 x 75

V = 120 V

Therefore, the voltage source required to provide 1.6 A of current through the 75 ohm resistance is 120 V.

This voltage is also the same for 50 ohms resistance but the current will be 2.4 A.

3 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK!!
ivolga24 [154]

R01= 14.1 Ω

R02=  0.03525Ω

<h3>Calculations and Parameters</h3>

Given:

K= E2/E1 = 120/2400

= 0.5

R1= 0.1 Ω, X1= 0.22Ω

R2= 0.035Ω, X2= 0.012Ω

The equivalence resistance as referred to both primary and secondary,

R01= R1 + R2

= R1 + R2/K2

= 0.1 + (0.035/9(0.05)^2)

= 14.1 Ω

R02= R2 + R1

=R2 + K^2.R1

= 0.035 + (0.05)^2 * 0.1

= 0.03525Ω

Read more about resistance here:

brainly.com/question/17563681

#SPJ1

5 0
2 years ago
THE MASS FOR OBJECT 1 is 107.01 grams what is the objects force in Newton’s answer please
Aleksandr [31]

Given that,

Mass of the object 1, m = 107.01 grams

To find,

Force on the object.

Solution,

The force acting on the object is gravitational force. The force is given by the formula as follow :

F = mg

g is acceleration due to gravity

F = 0.10701 kg × 9.8 m/s²

F = 1.048 N

So, the force acting on object 1 is 1.048 N.

5 0
3 years ago
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