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Lesechka [4]
1 year ago
6

If a football quarterback can throw the ball at 20.0 m/s, what is the furthest distance the quarterback could throw the ball neg

lecting air resistance?
Physics
1 answer:
kvasek [131]1 year ago
4 0

The furthest distance the quarterback could throw the ball neglecting air resistance is 81.63 meters.

The situation given above is an example of projectile motion.

The maximum distance up to which a projectile can be thrown is known as its range, which is given by the formula,

Range(R) = 2u^2 sin(2θ)/g

Here u is the maximum velocity of the projectile= 20 m/s

θ is the angle at which the projectile is launched = 45°

g is the acceleration due to gravity = 9.8 m/s^2

Putting the above values in the given equation,

The range comes out to be 81.63 meters.

Hence, the furthest distance the quarterback could throw the ball neglecting air resistance is 81.63 meters.

To know more about "projectile motion", refer to the following link:

brainly.com/question/11422992?referrer=searchResults

#SPJ4

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Answer:

a) Initial Value Problem

dv/dt = 4 - 0.1v

v(0) = 0

b) solution to the IVP

v(t) = 40(1 - e^(-t/10))

c) Limiting velocity

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Position of the car after 12 hours

X = 14,390 ft

Explanations:

The complete explanations of each of the sections contained in the question are in the files attached to this solution.

4 0
3 years ago
sedimentary rocks are formed due to the …..1-cooling of magna2 weathering of rocks 3 changes in pressure4 changes in temperature
Korolek [52]

Answer:

2

Explanation:

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4 0
3 years ago
An airplane pilot sets a compass course due west and maintains a speed of 220 km/h. after flying for a half hour she finds herse
timurjin [86]

The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.  

so airspeed due west is  = net speed - speed of plane = 240-220= 20 km/h.  

airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.  

the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h

the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.  

if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.

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the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.

5 0
3 years ago
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When a runner increases her speed from 75 m/s to 115 m/s in 25 s,her acceleration is _____
Angelina_Jolie [31]
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8 0
3 years ago
How much work do you need to do if you use a force of 3 Newtons to move a table 25 meters?
Harlamova29_29 [7]

The work needed if a force of 3N is used to move a table 25 metres is 75Nm (joules).

<h3>How to calculate work done?</h3>

Work is a measure of energy expended in moving an object. This means that no work is done if the object does not move.

Force is a physical quantity that denotes the ability to push, pull, twist or accelerate a body and which has a direction and is measured in Newtons.

Work done on an object can be calculated by multiplying the force applied to move the object by the distance the object moves as follows:

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Therefore, 75Nm is the work done on the table.

Learn more about work done at: brainly.com/question/2117638

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6 0
1 year ago
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