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kramer
1 year ago
5

Why does the skateboarder continue to move forward when he hits the trash? what is the unbalanced force?.

Physics
1 answer:
Anastasy [175]1 year ago
4 0

According to Newton's first law:  An item at relaxation will continue to be at relaxation until acted on with the aid of using an unbalanced force.

What are newton's laws of motion?

Newton's laws of motion are three basic laws of classical mechanics that describe the relationship between the motion of an object and the forces acting on it. These laws can be paraphrased as follows: A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force.

According to Newton's first law: An object at rest will remain at rest unless acted on by an unbalanced force. An object in motion continues in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

There is a force that moves the skater and his skate forward, after the hit, his speed is reduced, but this force is not completely counteracted, and that's why he continues moving forward.

To learn more about newton's law the link is given below:

brainly.com/question/25319016?

#SPJ4

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Unit of mass : kg

Unit of acceleration : m/s²

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Unit of force ➠ <u>kg m/s²</u>

SI unit : <u>N (newton)</u> or <u>kg m/s²</u>

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A ferris wheel has a radius of 36 feet and completes one revolution every 5.4 minutes. what is the speed of the ferris wheel (in
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An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It start
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Given :

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west.

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4 0
3 years ago
A uniformly charged ring of radius 10.0 cm has a total charge of 71.0 μC. Find the electric field on the axis of the ring at the
oee [108]

Answer:

General Expression: E = kql/(l² + r²)^(3/2)

(a) 6.3 MN/C

(b) 22.8 MN/C

(c) 6.1 MN/C

(d) 0.63 MN/C

Explanation:

The general expression for electric field along axis of a uniformly charged ring is:

<u>E = kqL/(L² + r²)^(3/2)</u>

where,

E = Electric Field Strength = ?

k = Coulomb's Constant = 9 x 10⁹ N.m²/C²

q = Total Charge = 71 μC = 71 x 10⁻⁶ C

L = Distance from center on axis

r = radius of ring = 10 cm = 0.1 m

(a)

L = 1 cm = 0.01 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.01 m)/[(0.01 m)² + (0.1 m)²]^(3/2)

E = (6390 N.m³/C)/(0.00101 m³)

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<u></u>

(b)

L = 5 cm = 0.05 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.05 m)/[(0.05 m)² + (0.1 m)²]^(3/2)

E = (31950 N.m³/C)/(0.00139 m³)

<u>E =  22.8 x 10⁶ N/C = 27.4 MN/C</u>

<u></u>

(c)

L = 30 cm = 0.3 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(0.3 m)/[(0.3 m)² + (0.1 m)²]^(3/2)

E = (191700 N.m³/C)/(0.03162 m³)

<u>E =  6.1 x 10⁶ N/C = 6.1 MN/C</u>

<u></u>

(d)

L = 100 cm = 1 m

Therefore,

E = (9 x 10⁹ N.m²/C²)(71 x 10⁻⁶ C)(1 m)/[(1 m)² + (0.1 m)²]^(3/2)

E = (639000 N.m³/C)/(1.015 m³)

<u>E =  0.63 x 10⁶ N/C = 0.63 MN/C</u>

8 0
3 years ago
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