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3 years ago

Name the compound formed when a copper cation that has a 2+ charge combines with a bromine anion that has a 1- charge.

2 answers:

6 0

The compound that is formed when a copper cation and a bromine anion reacts would be Copper (II) bromide. It will have a chemical formula CuBr2. This reaction is a synthesis reaction where two substances reacts to form one product.

Phoenix [80]3 years ago

4 0

Answer:

The compound is called copper (II) bromide or cupric bromide.

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Lina20 [59]

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Hydrogen Fluoride / HF

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2 years ago

Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy

barxatty [35]

Answer:

1. $S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

2. $Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

3.The electron affinity of $Mg^{2+}$ is zero.

4. $O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

Explanation:

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

$Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

The electronic configuration of Mg: $1s^{2}2s^{2}2p^{6}3s^{2}$

By the removal of two electrons from a magnesium element we get $Mg^{2+}$ ion.

$Mg^{2+}$ has inert gas configuration i.e, $1s^{2}2s^{2}2p^{6}$

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of $Mg^{2+}$ is zero.

The ionization energy of $O^{2-}$ is follows.

$O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

3 0

3 years ago

Trình bày sự hình thành phân tử CCl4 (lai hoá sp3)

Anna35 [415]

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8 0

3 years ago

Which of the following is NOT considered a branch of Chemistry?

mestny [16]

Answer:

Pure Chemistry -- is NOT considered a branch of Chemistry.

Explanation:

Second question is number 4.

4 0

3 years ago

Read 2 more answers

Using the periodic table, determine which material is most likely to be a good conductor. A. sodium B. bromine C. carbon D. oxyg

grandymaker [24]

A. Because sodium is a metal and metals are good conductors

7 0

3 years ago