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4 years ago

What is the relationship between air pressure and air temperature?

1 answer:

8 0

The relationship between the two is that air temperature changes the air pressure. For example, as the air warms up the molecules in the air become more active and they use up more individual space even though there is the same<span> number of molecules. This causes an </span>increase<span> in the air pressure.</span>

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A student jumps off of a cliff into a river 25.9 m below. If the student landed 20.7 m horizontally away from where they jumped

lord [1]

Their probably dead but I’m not sure

6 0

3 years ago

If you wanted to move an electron from the positive to the negative terminal of the battery, how much work W would you need to d

brilliants [131]

a lot of electric so that the battery can work

8 0

4 years ago

Why does the total amount of energy before and after any energy transformations remain the same?

Georgia [21]

The amount of energy before and after any energy transformations remain the same because energy cannot be created or destroyed. From the law conservation of energy; any time energy is transferred between two objects, or converted from one form into another, no energy is created and none is destroyed. The total amount of energy involved in the process remains the same.

3 0

3 years ago

Read 2 more answers

A bulldozer uses a 500 N force to push a load of dirt 16 m to the worksite. How much work

strojnjashka [21]

Explanation:

Force (F) = 500 N

Distance (d) = 16 m

work done (w) =?

We know that

w = F * d

= 500 * 16

= 8000 Joule.

The bulldozer performs 8000 Joule.

Hope it will help you :)❤

4 0

3 years ago

A stream of doubly ionized particles (2 protons) moves at a velocity of 3.0 × 104 m/s perpendicularly to a magnetic field of 0.0

max2010maxim [7]

The force on a charged particle on a magnetic field is given by:

$F=Bqv\sin\theta$

where B is the magnitude of the field, q is the charge of the particle, v is its velocity and θ is the angle between the field and the velocity of the particle.

In this case we have that:

• The magnitude of the field is 0.09 T.

• The charge of the particle is 3.2 x 10 –19C .

• The velocity is  3.0 × 10 4 m/s

• The angle between the field and the velocity is 90°, since they are perpendicular.

Plugging these we have:

$\begin{gathered} F=(0.09)(3.2\times10^{-19})(3\times10^4)\sin90 \\ F=8.64\times10^{-16}\text{ N} \end{gathered}$

Therefore, the force on the charge is:

$F=8.64\times10^{-16}\text{N}$

3 0

2 years ago