Speed is the size (absolute value) of the velocity.
Speed is a scalar. Velocity is a vector.
Answer:
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Explanation:
V = 5v
I = 1A
E = 38.9 Kj = 38900 j
t = ?
E = IVt
t = E/IV
t = 38900 ÷ (1 × 5)
t = 38900 ÷ 5
t = 7780 seconds
t = 7780/3600............( converting time in seconds to hours)
t = 2.16 hrs
Answer:
0.35
Explanation:
According to Newton's second law;
\sum Fx = ma
Fm - Ff =ma
Fm is the moving force = Wsin theta
Fm = 4(9.8)sin55
Fm = 32.1N
Ff is the frictional force = nmgcos theta
Ff = n(4)(9.8)cos55
Ff = 22.48n
Acceleration a = 6.0m/s²
Substitute the given values into the formula and get the coefficient of friction
32.11-23.48n = 4(6)
32.11-24= 23.48n
8.11 = 23.48
n = 8.11/23.48
n = 0.35
Hence the coefficient of friction is 0.35
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