Question

monochromatic light falls on a screen 1.70 m from two slits separated by 2.05 mm. the first- and second-order bright fringes are separated by 0.550 mm. what is the wavelength of the light? nm

Answer 1

The wavelength of the light is 663nm.

What is double slit interference pattern?

The wave effectively separates into two new waves that each expand out from one of the slits as it travels through both openings. Then, there is interference between these two waves. The interference pattern is made up of alternate bright and dark lines; the bright lines are referred to as fringes. The wavelength in a double-slit experiment can be calculated using the following equation:

λ $= yd / D$

where,

λ = wavelength of light source

D = distance between the screen and the slit

d = slit separation

Given,  

$y = 0.550 mm, d = 2.05 mm, D = 1.70m$

Subsituting the values in equation:

λ $= yd / D$

λ = $(0.550* 10^{-3} )(2.05* 10^{-3}) / 1.70$

λ $= 663nm$

The wavelength of the light is 663nm.

To know more about double slit interference, check out :

brainly.com/question/20366228

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