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Morgarella [4.7K]
1 year ago
10

A scientist decides to replicate an experiment completed by another scientist. Which statement describes something that would no

t affect the results of the replicated experiment?
A) The two experiments were completed by two different people.
B) The variables were not kept the same in both experiments.
C) The two scientists did not use the same equipment.
D) There were some measurements that were different in the two experiments.
Physics
1 answer:
tatyana61 [14]1 year ago
6 0

The statement describes something that would not affect the results of the replicated experiment is option A. (The two experiments were completed by two different people)

<h3>What is an experiment?</h3>

An experiment can be defined as a procedure carried out to support or refute a hypothesis, or determine the efficacy or likelihood of something previously untried.

Experiments helps in the provision of insight into the cause-and-effect by demonstrating what outcome occurs when a particular factor is manipulated.

If two experiments were completed by two different people, it would not affect the results if the experiment is replicated.

The purpose of any experiment is to test or verify a hypothesis

Learn more about experiments at: brainly.com/question/26117248

#SPJ1

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klasskru [66]
An element refers to a collection of atoms having the same number of protons and electrons (an atomic number). In each element there is a different atomic number due to a different amount of protons in the nucleus.

An isotope is a variation of an element that contains a different number of neutrons, therefore adding weight to the atom.

An ion is a charged atom, and its charge shows how many electrons it needs to gain or lose in order to become stable.
6 0
3 years ago
What is the potential energy of a 3kg ball that is on the ground?
ELEN [110]

This is where we have to admit that gravitational potential energy is
one of those things that depends on the "frame of reference", or
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         Potential energy = (mass) x (gravity) x (<em>height</em>).

So you have to specify <em><u>height above what</u></em> .

-- With respect to the ground, the ball has zero potential energy.
(If you let go of it, it will gain zero kinetic energy as it falls to
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-- With respect to the floor in your basement, the potential energy is

                 (3) x (9.8) x (3 meters) = 88.2 joules.

(If you let go of it, it will gain 88.2 joules of kinetic energy as it falls
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-- With respect to the top of that 10-meter hill over there, the potential
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                    (3) x (9.8) x (-10) = -294 joules

(Its potential energy is negative. After you let go of it, you have to give it
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5 0
3 years ago
I have an astronomy question... Spinning up the solar nebula. The orbital speed of the material in the solar nebula at Pluto's a
attashe74 [19]
<span>The angular momentum of a particle in orbit is 

l = m v r 

Assuming that no torques act and that angular momentum is conserved then if we compare two epochs "1" and "2" 

m_1 v_1 r_1 = m_2 v_2 r_2 

Assuming that the mass did not change, conservation of angular momentum demands that 

v_1 r_1 = v_2 r_2 

or 

v1 = v_2 (r_2/r_1) 

Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have 

v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s

Therefore, </span> the orbital speed of this material when it was 40,000 AU from the sun is <span>4.875E-3 km/s.

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</span>
3 0
3 years ago
Krishne wants to measure the mass and volume of a key. Which tools should she use? a balance and a beaker of water a balance and
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8 0
3 years ago
Read 2 more answers
a vector a has components a x equals -5.00 m in a y equals 9.00 meters find the magnitude and the direction of the vector
Murrr4er [49]

Answer:

The magnitude = 10.30 m

The direction of the vector proceeds at angle of 119.05°

Explanation:

Given that:

A vector \bar A has component A_x = -5 m and A_y = 9 m

The magnitude of vector  \bar A can be represented as:

\bar A  = \sqrt{A_x^2 + A_y^2}

\bar A  = \sqrt{(-5)^2 + (9)^2}

\bar A  = \sqrt{25 + 81}

\bar A  = \sqrt{106}

\bar A  = 10.30 m

If we make \bar A  an angle \theta with y- axis:

Then;   tan \theta  = \frac{A_x}{A_y}

tan \theta  = \frac{5}{9}

tan \theta  = 0.555

\theta  = tan⁻¹ (0.555)

\theta  = 29.05°

Angle with positive x-axis = 90 + \theta  

= 90° + 29.05°

= 119.05°

5 0
3 years ago
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