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Morgarella [4.7K]
1 year ago
10

A scientist decides to replicate an experiment completed by another scientist. Which statement describes something that would no

t affect the results of the replicated experiment?
A) The two experiments were completed by two different people.
B) The variables were not kept the same in both experiments.
C) The two scientists did not use the same equipment.
D) There were some measurements that were different in the two experiments.
Physics
1 answer:
tatyana61 [14]1 year ago
6 0

The statement describes something that would not affect the results of the replicated experiment is option A. (The two experiments were completed by two different people)

<h3>What is an experiment?</h3>

An experiment can be defined as a procedure carried out to support or refute a hypothesis, or determine the efficacy or likelihood of something previously untried.

Experiments helps in the provision of insight into the cause-and-effect by demonstrating what outcome occurs when a particular factor is manipulated.

If two experiments were completed by two different people, it would not affect the results if the experiment is replicated.

The purpose of any experiment is to test or verify a hypothesis

Learn more about experiments at: brainly.com/question/26117248

#SPJ1

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Answer:

The answer is A

Explanation:

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A motorcyclist heading east through a small town accelerate at constant 4.0meter per seconds square after he leaves the limits.
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A) The position at t = 2.0 sec is 43.0 m east

B) The position is 55 m east

Explanation:

A)

In order to solve the problem, we take the east direction as positive direction.

We know that:

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- at t = 0, the initial velocity of the motorcyclist is v_0 = 15.0 m east

- The acceleration of the motorcyclist is constant and it is a=4.0 m/s^2

Since the motion is a uniformly accelerated motion, the position of the motorcylist is given by the expression

x(t)=x_0 + v_0t + \frac{1}{2}at^2

where t is the time.

Substituting t = 2.0 s, we find the position:

x(2.0)=(5.0)+(15)(2.0)+\frac{1}{2}(4.0)(2.0)^2=43 m

B)

The velocity of the motoryclist can be found by calculating the derivative of the position. Therefore, it is:

v(t)=x'(t)=v_0 + at

where:

v_0=15.0 m/s is the initial velocity

a=4.0 m/s^2 is the acceleration

We want to find the time t at which the velocity is

v = 25 m/s

Solving the equation for t,

t=\frac{v-v_0}{a}=\frac{25-15}{4}=2.5 s

And therefore, the position at t = 2.5 s is:

x(2.5s)=5.0+(15.0)(2.5)+\frac{1}{2}(4)(2.5)^2=55 m

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Hence, option B is correct.

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Read 2 more answers
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