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3 years ago

Describe the motionof an object that gas acceleration of 0 m/s

Physics

1 answer:

Maru [420]3 years ago

3 0

If an object has acceleration of zero meters per second², then the object is traveling at a constant speed.

Note: The constant speed doesn't have to be zero, so the object is not necessarily at rest. It can be moving at any speed, as long as the speed doesn't change. (If the speed changed, then the acceleration wouldn't be zero.)

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initially, a bowl holds 15 m^3 of water. an object is dropped into the bowl and the new volume of the water is 25 m^3. what is t

marusya05 [52]

Explanation:

The new volume of water = 25 ml

The old volume of water = 15 ml

The difference = 25 - 15 but what are the units?

Since the question asks for force, the units must start out as 10 mL

In water 1 mL has a mass of 1 gram, so the answer is 10 grams.

Grams are units of mass, not weight. You should convert this into newtons.

10 grams = 1/1000 = 0.01 kg

1 kg has a weight of 9.81 Newtons

0.01 kg has a weight 0.081 Newtons

If you have never seen a Newton before, then the answer is 10 grams

3 0

2 years ago

8. (Liquids, Gas) have no definite shape, and no definite volume.<br> A)Liquid<br> B)Gas

Fynjy0 [20]

B. gas has no definite shape or volume. liquid has definite volume but no definite shape

4 0

2 years ago

A long, solid rod 5.3 cm in radius carries a uniform volume charge density. Part A If the electric field strength at the surface

Blizzard [7]

Answer:

$\rho = 7.35\times \muC/m^3$

Explanation:

given,

Radius of the solid rod, R = 5.3 cm

Electric field strength,E = 22 kN/C

Let the volume charge density be ρ

From Gauss law

$E = \dfrac{Rl}{2\epsilon_0}$

ε₀ is the permitivity of free space

R is the radius of the rod

and also,

$\rho=\dfrac{2E\epsilon_0}{R}$

ρ is the volume charge density

$\rho=\dfrac{2\times 22\times 10^{3}\times 8.854\times 10^{-12}}{0.053}$

$\rho = 7.35\times 10^{-6}\ C/m^3$

$\rho = 7.35\times \muC/m^3$

Hence, the volume charge density is equal to $\rho = 7.35\times \muC/m^3$

6 0

2 years ago

!!!!!!!!!!!PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!

Alexeev081 [22]

You might want to do a re-erp on this equation

5 0

2 years ago

Read 2 more answers

A and B start walking in the same direction at the same time around a circular park of diameter 4200 m. If A walks 10 m more tha

Liono4ka [1.6K]

Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π time for A to again catch B

N = 1.39 * 24700 Answer:

Va = 5000 m / 3600 s = 1.39 m/s

(Va - Vb) 60 = 10

Vb = Va - .167 = 1.22 m/s

(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap

.17 T = 4200 Π

T = 24700 Π time for A to again catch B

N = 1.39 * 24700 Π / (4200 Π) = 8.2 laps

A will make 8 but not 9 rounds before catching B

6 0

1 year ago