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Flauer [41]
3 years ago
11

A skier starts from rest down a slope 500.0 M long, the skier accelerates at a constant rate of 2.00 m/s/s, what's the velocity

of the skier at the bottom of the hill
Physics
1 answer:
nevsk [136]3 years ago
8 0
We can use the kinematic equation
(v_f)^2 = (v_i)^2 + 2*a*d
where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance

we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
or 44.7 m/s   [if you are rounding this by significant figures]
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3 0
3 years ago
what is the acceleration of a car that slows down from 60m/s to 40 m/s during a period of 10 seconds?
algol [13]

The acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

Answer:

Explanation:

Acceleration exerted by any object in order of decrease in the speed is termed as deceleration. In other words , negative acceleration or acceleration acting in opposite direction to stop the motion of any object is termed as deceleration. The magnitude of acceleration and deceleration is same only the direction is completely opposite to each other. So the negative sign will be obtained for acceleration value of any object whose velocity slows down from initial velocity.

Here , the initial velocity was 60 m/s and the final velocity is slowed down to 40 m/s in time 10 s.

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Thus, the acceleration of the car is stated as -2 m/s², while the deceleration of the car is termed as 2 m/s².

5 0
3 years ago
A constant magnetic field passes through a single rectangular loop whose dimensions are 0.35 m × 0.55 m. The magnetic field has
Pani-rosa [81]

Answer:

Part a)

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Part b)

\frac{dA}{dt} = 0.43 m^2/s

Explanation:

Part a)

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\phi_1 = 0.17 Wb

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now EMF is given as

EMF = \frac{\phi_1 - \phi_2}{\Delta t}

EMF = \frac{0.17 - 0}{0.45}

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Part b)

If magnetic field is constant while Area is changing

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E = Bcos65 \times \frac{dA}{dt}

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