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erik [133]
1 year ago
7

a strong wind blows over the house shown in the figure. the wind is much stronger over the house's roof than lower down, and the

house has an open chimney. a window on the ground floor is open, and so are the doors inside the house. which way will air flow through the house?
Physics
1 answer:
lana66690 [7]1 year ago
8 0

A strong wind blows over the house shown in the figure. The wind is much stronger over the house's roof than lower down, and the house has an open chimney. a window on the ground floor is open, and so are the doors inside the house.  Air flow  in the window and out the chimney .

Bernoulli's principle: Within a horizontal flow of fluid, points of higher fluid speed will have less pressure than points of slower fluid speed.

Since , the wind is much stronger over the house's roof than down , that means there will be less pressure over the house's roof than down the house . Since , gas travel from high pressure to low pressure . Hence , air flow  in the window and out the chimney .

To learn more about Bernoulli's principle here :

brainly.com/question/2249706

#SPJ4

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What is Latent heat and also give types.<br>​
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Answer:

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Explanation:

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Speed is a scalar quantity that describes only the
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magnitude of the velocity

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3 years ago
What is the power of a refrigerator with voltage 110 V and<br> current 0.8 A?
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8 0
3 years ago
A cannon elevated at 40 degrees is fired at a wall 300m away on level ground. The initial speed of the cannonball is 89m/s How l
lianna [129]
For the answer to the question above, we'll have to use these formulas.

A) to find time to travel the 300m,
just find horizontal component of the velocity and divide.
ie x=89 x t x cos 40, t=x/89 x cos 40 

<span>B) y=vtsin 40 - gt^2/2, just sub in
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I believe you can do the rest.

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3 0
3 years ago
A "biconvex" lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvat
Stolb23 [73]

Answer: f=150cm in water and f=60cm in air.

Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:

\frac{1}{f} = (nglass - ni)(\frac{1}{R1} - \frac{1}{R2}).

nglass is the index of refraction of the glass;

ni is the index of refraction of the medium you want, water in this case;

R1 is the curvature through which light enters the lens;

R2 is the curvature of the surface which it exits the lens;

Substituting and calculating for water (nwater = 1.3):

\frac{1}{f} = (1.5 - 1.3)(\frac{1}{10} - \frac{1}{15})

\frac{1}{f} = 0.2(\frac{1}{30})

f = \frac{30}{0.2} = 150

For air (nair = 1):

\frac{1}{f} = (1.5 - 1)(\frac{1}{10} - \frac{1}{15})

f = \frac{30}{0.5} = 60

In water, the focal length of the lens is f = 150cm.

In air, f = 60cm.

5 0
4 years ago
Read 2 more answers
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