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Sidana [21]
2 years ago
10

How can gravity be simulated in an orbiting space station?.

Physics
1 answer:
Alex777 [14]2 years ago
6 0

Answer:

A spinning space station will have centrifugal force acting on the inhabitants which if adjusted right can simulate the force of gravity on Earth

Explanation:

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SCIENCE whoever gets this first will get a brainlest
gulaghasi [49]

Answer:

im not 100% sure i should be doing this but i found a website that will help a ton.

https://geo.libretexts.org/Courses/Gettysburg_College/Book%3A_An_Introduction_to_Geology_(Johnson_Affolter_Inkenbrandt_and_Mosher)/02%3A_Plate_Tectonics/2.01%3A_Alfred_Wegener%E2%80%99s_Continental_Drift_Hypothesis

6 0
3 years ago
Read 2 more answers
What is the smallest time interval in which a 5.7 T magnetic field can be turned on or off if the induced emf around the patient
VLD [36.1K]

The smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

<h3>Emf induced in the coil</h3>

The emf induced in the coil is calculated as follows;

emf = dФ/dt

where;

  • dФ is change in flux
  • dt is change in time

0.12 = 5.7/dt

dt = 5.7/0.12

dt = 47.5 s

Thus, the smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

Learn more about emf here: brainly.com/question/13744192

#SPJ11

3 0
2 years ago
On the decibel scale,an increase of 1 dB means that sound intensity is increased by a factor of ________?
Maurinko [17]


Your answer would be 10 decibels
4 0
3 years ago
Read 2 more answers
Locomotion is the act of staying stationary. <br><br> True <br> False<br><br> 20 POINTS
Fittoniya [83]

Answer:

False

Explanation:

Locomotion is associated with movement.

The word is derieved from two Latin words,

Loco----place

Motio----to move.

8 0
3 years ago
A car starts from rest with an acceleration of 6
mrs_skeptik [129]

Answer:

t=16.67s

Explanation:

From the question, acceleration from 6m/s^2  \ to \ 0m/s^2 in 10 seconds.

Acceleration function can be written as:-

a_t=6-0.6t

From the acceleration equation, we can obtain the velocity equation:

v(t)=\int\limits^t_b {0} \, dv=\int\limits^t_0 {a(t)} \, dt\\v(t)=\int\limits^t_0 {(6-06t)} \, dt=6t-0.3t^2\\*dv=a(t)dt

We calculate velocity after 10sec from the above v(t) as 30m/s.

To obtain distance travelled after 10 seconds:-

S=\int\limits^{10}_0 {6t-0.3t^2} \, dt=|3t^2-0.1t^3|   \ *lims(10,0)\\ S=200m

Therefore 200m is for 10seconds, and next 200m at 30m/s

Total time=10+\frac{200}{30}=16.67s

4 0
4 years ago
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