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astraxan [27]
1 year ago
14

What is Newton's third law of motion?​

Physics
2 answers:
slavikrds [6]1 year ago
5 0

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions

<h2>Explanation:</h2>

Newton’s Third Law: Action & Reaction

Whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first.

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions.

Examples of action and reaction involving aerodynamics:

  •    The motion of lift from an airfoil, the air is deflected downward by the airfoil’s action, and in reaction, the wing is pushed upward.
  •    The motion of a spinning ball, the air is deflected to one side, and the ball reacts by moving in the opposite
  •    The motion of a jet engine produces thrust and hot exhaust gases flow out the back of the engine, and a thrusting force is produced in the opposite direction

----------------

HOPE THIS HELPS <3

zzz [600]1 year ago
3 0
<h2>Answer : </h2>

Newton's Third law of motion states :

" Every action has an equal and opposite reaction "

i.e If a force is applied by an object A on another object B then that object B also exerts a foce on object A, that is of same magnitude and opposite direction to the force applied by object A.

Ex - A book on a table exerts gravitational force on the table and table exerts back a normal force on the book.

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Why is work measured in
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Answer:

C) the equation consists of two factors:

work = force * distance

W = F · S

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Terry says that if an object has no acceleration, then no forces are exerted on it. Sherry doesn't agree, but can't provide an e
crimeas [40]
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A spaceship accelerates uniformly for 1220km how much time is needed for the spaceship to increase its speed from 11.1km/s to 11
snow_lady [41]

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s

<h3>Data obtained from the question</h3>

The following data were obtained from the question given above:

  • Initial velocity (u) = 11.1 Km/s
  • Final velocity (v) = 11.7 Km/s
  • Distance (s) = 1220 Km
  • Time (t) =?

<h3>How to determine the time</h3>

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:

s = (u + v)t / 2

Cross multiply

(u + v)t = 2s

Divide both sides by (u + v)

t = 2s / (u + v)t

t = (2 × 1220) / (11.1 + 11.7)

t = 2440 / 22.8

t = 107 s

Thus, the time taken for the spaceship to change its speed is 107 s

Learn more about speed:

brainly.com/question/680492

Learn more about velocity:

brainly.com/question/3411682

#SPJ1

6 0
2 years ago
I need help with this please thank you!
Tresset [83]

D. A beam balance does not measure mass; it measures weight. The gravitational force of attraction between the earth and an object depend on the mass of the object. ... The beam balance measures the force F exerted by the mass on the beam balance

8 0
3 years ago
and an ideal spring of unknown force constant. The oscillator is found to have a period of 0.157 s and a maximum speed of 2 m/s
DENIUS [597]

Answer:

k = 1073.09 N/m

A = 0.05 m

Explanation:

Given:

- Time period T = 0.147 s

- maximum speed V_max = 2 m/s

- mass of the block m = 0.67 kg

Find:

- The spring constant k

- The amplitude of the motion A.

Solution:

- A general simple harmonic motion is modeled by:

                                     x (t) = A*sin(w*t)

- The velocity of the above modeled SHM is:

                                     v = dx / dt

                                     v(t) = A*w*cos(w*t)

- Where A is the amplitude in meters, w is the angular speed rad/s and time t is in seconds.

- We can see that maximum velocity occurs when (cos(w*t)) maximizes i.e it is equal to 1 or -1. Hence,

-                                      V_max = A*w

- Where w is related to mass of the object and spring constant k as follows,

                                       w = sqrt ( k / m )

- The relationship between w angular speed and Time period T is:

                                       w = 2*pi / T

- Equating the above two equations we have,

                                        m*(2*pi / T)^2 = k

- Hence,                           k = 0.67*(2*pi / 0.157)^2

                                        k = 1073.09 N / m

- So, amplitude A is:

                                        A = V_max*sqrt ( m / k )

                                        A = 2*sqrt ( 0.67 / 1073.09 )

                                        A = 0.05 m      

6 0
4 years ago
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