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docker41 [41]
2 years ago
14

Amanda paired with Janice while Deja paired with Eden for a chemistry project. For the Earth science project, Amanda paired with

Eden while Deja paired with Janice. Which type of chemical reaction does the situation demonstrate?
Decomposition reaction
Single replacement
Synthesis reaction
Double replacement reaction
Chemistry
2 answers:
Black_prince [1.1K]2 years ago
4 0

Answer:

A

Explanation:

pashok25 [27]2 years ago
3 0

The chemical reaction that the situation demonstrates would be a double replacement reaction.

In double replacement reactions, the two reactants participating in the reaction are similarly built in terms of their chemical bonds and they exchange ions to form the products of the reaction. Two products are also formed from the two reactants.

It is as opposed to single replacement reactions in which the two reactants are not similar bond-wise. One of the reactants replaces or displaces one of the ions in another reactant.

In this case, the situation can be represented as follows:

Amanda-Janice + Deja-Eden ----> Amanda-Eden + Deja-Janice

Thus, it is a form of double replacement reaction.

More on double replacement reactions can be found here: brainly.com/question/392491?referrer=searchResults

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Answer:

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2 years ago
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C₇H₆O₂ + O₂ -->CO₂ +H₂O Find the chemical reaction
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Answer:

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Explanation:

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For the reaction N2(g) + 2H2(g) → N2H4(l), if the percent yield for this reaction is 100.0%, what is the actual mass of hydrazin
barxatty [35]

Answer:

53.6 g of N₂H₄

Explanation:

The begining is in the reaction:

N₂(g) + 2H₂(g) → N₂H₄(l)

We determine the moles of each reactant:

59.20 g / 28.01 g/mol = 2.11 moles of nitrogen

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Our 2.11 moles of N₂ may react to (2.11 . 2) /1 = 4.22 moles of H₂, but we only have 3.35 moles. The hydrogen is the limiting reactant.

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Then, 3.35 moles, may produce (3.35 . 1)/2 = 1.67 moles of N₂H₄

Let's convert the moles to mass:

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Remark

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So essentially what happens is that X is one space to the left on the periodic table. But let's solve this a little bit more formally.

Solution

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64 = z

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