The new voltage value of parallel-plate capacitor is 800 V.
We need to know about the capacitance of the parallel-plate capacitor to solve this problem. The capacitance of the parallel-plate capacitor depends on the charge and voltage. It can be written as
C = Q/V
where C is capacitance, Q is charge and V is voltage.
Capacitance also can be calculated by the area and distance between capacitor plate
C = εo . A / d
where εo is vacuum permittivity (8.85 x 10¯¹² F/m), A is area of plate and d is distance.
From the question above, we know that
V1 = 200 V
d1 = d
d2 = 4 d
By substituting the given parameters, we can calculate the voltage
εo . A / d = Q/V
The voltage is proportional to the distance of plate. Hence, the ratio of voltage will be
V1 / V2 = d1 / d2
200 / V2 = d / 4d
V2 = 4 x 200
V = 800 N
Find more on parallel-plate capacitor at: brainly.com/question/13578522
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