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anastassius [24]
11 months ago
7

15) a current carrying loop of wire lies flat on a table top. when viewed from above, the current moves around the loop in a cou

nterclockwise sense. for points inside the loop, the magnetic field caused by this current a) circles the loop in a clockwise direction. b) circles the loop in a counterclockwise direction. c) points straight up. d) points straight down. e) is zero.
Physics
1 answer:
Maksim231197 [3]11 months ago
6 0

The correct answer is option C.

Maxwell right hand thumb rule: if we hold a current carrying conductor in our right hand such that the thumb indicates the direction of current then the curling of fingers shows the direction of magnetic field around the conductor.

Here the current is counterclockwise so by use of Maxwell right hand thumb rule the direction of magnetic field is straight up.

Using Fleming right hand rule that States that if the fore-finger, middle finger and the thumb of left hand are stretched mutually perpendicular to each other, such that fore-finger points in the direction of magnetic field, the middle finger points in the direction of the motion of positive charge, then the thumb points to the direction of the force.

So, the current, when viewed from above, seems to move around loop in counterclockwise direction points straight up is because of Maxwell's Thumb Rule.

To know more about magnet, refer: brainly.com/question/17143116

#SPJ4

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Why are isotopes not shown on the periodic table
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A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr
Zinaida [17]

Answer:

The initial speed of bullet is "164 m/s".

Explanation:

The given values are:

mass of bullet,

m'=9.00 \ g

or,

    =0.009 \ kg

mass of wooden block,

m=1.20 \ kg

speed,

s=0.390 \ m

Coefficient of kinetic friction,

\mu=0.20

As we know,

The Kinematic equation is:

⇒  v^2=u^2+2as

then,

Initial velocity will be:

⇒  u=v^2-2as

        =v^2-2 \mu gs

On substituting the given values, we get

⇒  u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}

       =\sqrt{-1.5288}

       =1.23 \ m/s

As we know,

The conservation of momentum is:

⇒  mu=m'u'

or,

⇒ Initial speed, u'=\frac{mu}{m'}

On substituting the values, we get

⇒                            =\frac{1.20\times 1.23}{0.009}

⇒                            =\frac{1.476}{0.009}

⇒                            =164 \ m/s                              

3 0
2 years ago
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