Answer:
The heat contained is 1236 Joules
Explanation:
As we know
T
Where
T is the change in temperature
m is the mass in grams
c is the specific heat of water (ice) = 2.06 joules/gram
Substituting the given values, we get -
Joules
Its C. It has to be equivalent to the number divided or multiplied by 5.
Answer: 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of 
Explanation:
The balanced decomposition reaction is shown as

moles of 
According to stoichiometry:
2 moles of
gives = 3 moles of flourine gas
Thus 0.36 moles of
gives =
of flourine gas
Using ideal gas equation :

P = pressure of gas = 1 atm ( at STP)
V = Volume of gas = ?
n = moles of gas = 0.54
R = gas constant = 0.0821 L atm/Kmol
T = temperature = 273 K ( at STP)
Putting the values we get :


Thus 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of 
Given ,
Mass of sample of cobalt = 27 g
density of sample of cobalt = 9g/cm^3
We know that ,
Density = mass of sample/volume of sample
From that relation ,
We can deduce the following as
Volume = mass of sample/density of sample
Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3
The volume is