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Artyom0805 [142]
1 year ago
13

Calculate the pH of milk with a hydrogen ionconcentration of 4.25 x 10^-7 mol dm-3. Show all steps ofyour calculations and inclu

de the correct units
Chemistry
1 answer:
yulyashka [42]1 year ago
5 0

Answer:

6.37.

Explanation:

What is given?

[H (+)] = 4.25 x 10⁻⁷ mol/dm³

Step-by-step solution:

First, let's see the formula to calculate the pH based on the hydrogen ion concentration (H (+)):

pH=-log\lbrack H^+].

*Logarithm must be in base 10!

Our given concentration of hydrogen ion is 4.25 x 10⁻⁷ mol/dm³. Remember that the units of concentration must be in M (mol/L) but in this case, 1 dm³ equals 1 L, so based on this, we have that:

4.25\cdot10^{-7}\frac{mol}{dm^3}=4.25\cdot10^{-7}\frac{mol}{L}.

So, we can replace this value in the formula of pH:

pH=-log\lbrack4.25\cdot10^{-7}]\approx6.37.

The pH of milk would be 6.37 which means that is slightly acid (weak acid).

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Read that From picture and tell me the answer please​
Dafna11 [192]

Answer:

1g Hydrogen

Explanation:

<h3><u>Getting</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>equation</u><u>:</u></h3>

Calcium in water reacts vigorously to give a cloudy white <em>Precipitate</em><em> </em>(compound) called Calcium hydroxide alongwith the evolution of Hydrogen gas.

\boxed{ \mathsf{Ca + H_2O \rightarrow Ca(OH)_2 + H_2}}

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Balancing</u><u> </u><u>the</u><u> </u><u>equation</u><u>:</u><u> </u></h3>

This reaction is not in it's balanced form! The number of atoms of Hydrogen on the left is 2 while that on the right is 4,I.e.,they're not equal.

Adding a 2 in front of H2O solves the problem by making the number of atoms of each element on both the sides equal.

\mathsf{Ca +2 H_2O \rightarrow Ca(OH)_2 + H_2}

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Observations</u><u>:</u></h3>

Looking into the equation more carefully, we see:

<u><em>1</em><em> </em></u><em>atom</em><em> </em><em>of</em><em> </em><em>Calcium</em><em> </em><em>reacts</em><em> </em><em>with</em><em> </em><em><u>2</u></em><em> </em><em>molecules</em><em> </em><em>of</em><em> </em><em>water</em><em> </em><em>to</em><em> </em><em>give</em><em> </em><u><em>1</em><em> </em></u><em>molecule</em><em> </em><em>of</em><em> </em><em>Calcium</em><em> </em><em>Hydroxide</em><em> </em><em>alongwith</em><em> </em><em><u>1</u></em><em> </em><em>molecule</em><em> </em><em>of</em><em> </em><em>Hydrogen</em><em> </em><em>gas</em><em>.</em>

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Gram</u><u> </u><u>atomic</u><u> </u><u>and</u><u> </u><u>molecular</u><u> </u><u>masses</u><u> </u></h3>

<u>Mass</u><u> </u><u>of</u><u> </u><u>one</u><u> </u><u>atom</u><u> </u><u>of</u><u> </u><u>Calcium</u><u> </u>= it's gram atomic mass

= 40 g

<u>Mass of one "molecule" of Hydrogen</u>

= it's Gram molecular mass

= gram mass of one atom × number of atoms in one molecule

= 1 × 2

= 2 g

So,

according to our observation:

One atoms of Calcium gives one molecule of Hydrogen <em>(during the particular reaction)</em>

=><u> 40g of Calcium gives = 2g of Hydrogen</u>

•°• 1 g of Calcium gives = \frac{2}{40}

= \frac{1}{20} g Hydrogen

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3><u>Answer</u><u>:</u></h3>

We're provided with 20g of Calcium,

=> 20g of Calcium gives = 20 × \frac{1}{20} g H2

<u>= 1 g H2</u>

_______________

Hope this helps!

6 0
3 years ago
Consider the following data showing the initial rate of a reaction (A→products) at several different concentrations of A.
OlgaM077 [116]

Answer:

(1) order = 2

(2) R = K [A]²

Explanation:

Given the reaction:

A--------->Product

The rate constant relation for the reaction is given as:

R(i) = K [A]............(*)

Where R(I) is rate constant at different concentration of A.

Taking the rate constant as R1, R2 and R3 for the different concentrations respectively. Then the following equations results

0.011 = K [0.15] ⁿ.........(1)

0.044 = K [0.30]ⁿ .......(2)

0.177 = K [0.60]ⁿ .........(3)

Dividing (2) by (1) and (3) by (1)

Gives:

0.044/0.011 = [0.3/0.15]ⁿ

4 = 2ⁿ; 2² = 2ⁿ; n = 2

Similarly

0.177/0.011 = [0.60/0.15]ⁿ

16.09 = 4ⁿ

16.09 = 16 (approximately)

4² = 4ⁿ ; n = 2

Hence the order of the reaction is 2.

The rate law is R = K [A]²

4 0
3 years ago
-FeS2+-O2-&gt;-Fe2O3+-SO2 What coefficient should be placed in front of SO2 to balance the equation?
NISA [10]

Answer:

8 should be placed in front of SO₂.

Explanation:

The easiest way to solve this question is by writing the <u>entire</u> balanced equation:

4FeS₂ + 11O₂ -> 2Fe₂O₃ + 8SO₂

We can achieve this by first balancing the Fe, then S, and finally the O.

We can also double check our answer by counting the number of each element on both sides:

-Reactants: 4 Fe, 8 S, 22 O

-Products: 4 Fe 8 S, 22 O

Since they match, our equation is balanced, and the coefficient in front of SO₂ is 8.

8 0
3 years ago
An object accelerates 8.2 m/s2 when a force of 20.1 Newton's is applied to it. What is the mass of the object?
Shalnov [3]
Hey it's me again haha!

the answer to your question is:

answer: so f=20.1

a=8.2

m=?

f=ma

20.1 = 8.2*m in

20.1/8.2=m

so the answer is around 2.45 something!
also i'm sorry this question had be stumbled!
5 0
3 years ago
Read 2 more answers
5. You are investigating an arson scene and you find a corpse in the rubble, but you suspect that the victim did not die as a re
Marina CMI [18]

Answer:

See the answer below.

Explanation:

Fire has three major components:

  • Heat
  • Smoke
  • Gases ( in form of CO, CO2 etc)

If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.

If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.

<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>

8 0
3 years ago
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