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3 years ago

A roast beef weighs 5.65 kilograms. how many grams does it weigh?

Chemistry

2 answers:

dolphi86 [110]3 years ago

8 0

5,650 grams for the Roast beef

romanna [79]3 years ago

4 0

Yo do kilograms to grams you times it by 1000. 5.65*1000=5650 grams.

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Describe how lead sulfate can be prepared using silver hydroxide

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Answer:

i would have to add and divide

Explanation:

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2 years ago

Draw the structure for 1-nitrobutane, making sure to add all non-zero formal charges.

TiliK225 [7]

The molecular structure of 1-nitrobutane is $C_{4} H_{9} NO_{2}$ . The structure of 1-nitrobutane is shown below.

An atom's formal charge would be determined by the covalent model of chemical bonding, which assumes that almost all chemical bonds include equal sharing of electrons among all atoms, regardless their relative electronegativity.

The structure for 1-nitrobutane, making sure to add all non-zero formal charges

There are four kind of molecule present in 1-nitrobutane and they are carbon, hydrogen , nitrogen and oxygen. Nitrogen is bonded with two oxygen atom out of them one oxygen atom is attached with single bond and second oxygen atom is bonded with double bond. Nitrogen has positive charge whereas oxygen has negative charge.

It is a kind of alkane in with nitro group is attached with alkane group.

To know more about 1-nitrobutane

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1 year ago

What is the empirical formula of a compound that is 41.4% Strontium, 13.24%

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Answer:

Empirical Formula N2O6Sr Strontium Nitrate

Explanation:

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2 years ago

What is not a step of the scientific method

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3 years ago

Read 2 more answers

A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

Archy [21]

Answer:

a) 0.003512 moles

b) Moles C= 0.04214 moles carbon

Moles H = 0.07726 moles hydrogen

Moles O = 0.03863 moles of oxygen

c) C atoms = 2.54 *10^22 carbon atoms

H atoms = 4.65 *10^22 hydrogen atoms

O atoms = 2.33 *10^22 oxygen atom

Explanation:

Step 1: Data given

Mass of sucrose = 1.202 grams

Molar mass of sucrose = 342.3 g/mol

Step 2: Calculate moles of sucrose

Moles sucrose = Mass sucrose / molar mass sucrose

Moles sucrose = 1.202 grams / 342.3 g/mol

Moles sucrose = 0.003512 moles

Step 3: Calculate moles of each element

For 1 mol of C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen

Moles C: 12*0.003512 = 0.04214 moles carbon

Moles H: 22* 0.003512 = 0.07726 moles hydrogen

Moles O: 11* 0.003512 = 0.03863 moles of oxygen

Step 4: Calculate the number of atoms

C atoms = 6.022 *10^23 / mol * 0.04214 moles = 2.54 *10^22 atoms carbon

H atoms = 6.022 * 10^23 / mol * 0.07726 moles = 4.65 *10^22 atoms H

O atoms = 6.022 * 10^23 / mol * 0.03863 moles = 2.33 *10^22 atoms O

0.003512 moles of sucrose containse 6.022 *10^23 * 0.003512 = 2.11 * 10^21 sucrose molecules

7 0

3 years ago