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KengaRu [80]
3 years ago
14

You are driving on a freeway and notice a small car (very small) cut off a big truck. Explain why it is a bad idea for the small

car to cut off a very big truck?
Physics
1 answer:
Leno4ka [110]3 years ago
7 0

Answer: small cars can stop and go fast big trucks can not

Explanation:

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The federal government spends the most on which of the following?
sveta [45]
As Figure A suggests, Social Security is the single largest mandatory spending item, taking up 38% or nearly $1,050 billion of the $2,736 billion total. The next largest expenditures are Medicare and Income Security, with the remaining amount going to Medicaid, Veterans Benefits, and other programs.
7 0
3 years ago
What is the mechanical adventure of a machine with an input force of 63 pounds and an output force of 275 pounds?
madreJ [45]

mech advantage = load/effort = 275/63=4 and a bit

mech adventure ???

5 0
3 years ago
Un cuerpo se mueve, partiendo del reposo, con una aceleración constante de 8 m/s². Calcular la velocidad que tiene al cabo de 5s
nataly862011 [7]

Answer:

v = 40 m / s

Explanation:

Let's use the expressions for accelerated motion

         v = v₀ + a t

where vo is the initial velocity, at the acceleration and t is the time.

as the body starts from rest its initial velocity is zero

         v = 0 + at

let's calculate

         v = 8  5

         v = 40 m / s

8 0
2 years ago
The position of a particle moving along the x axis varies in time according to the expression x = 4t 2, where x is in meters and
Pie

Answer:

a) X = 17.64 m

b) X = 17.64 + 4∆t^2 + 16.8∆t

c) Velocity = lim(∆t→0)⁡〖∆X/∆t〗 = 16.8 m/s

Explanation:

a) The position at t = 2.10s is:  

                 X = 4t^2

                 X = 4(2.10)^2

                 X = 17.64 m

b) The position at t = 2.10 + ∆t s  will be:

                 X = 4(2.10 + ∆t)^2

                 X = 17.64 + 4∆t^2 + 16.8∆t  m

c) ∆X is the difference between position at t = 2.10s and t = 2.10 + ∆t so,

                 ∆X= 4∆t^2 + 16.8∆t

Divide by ∆t on both sides:  

                ∆X/∆t =  4∆t + 16.8

 Taking the limit as ∆t approaches to zero we get:  

              Velocity =lim(∆t→0)⁡〖∆X/∆t〗 = 4(0) + 16.8

              Velocity = 16.8 m/s

 

8 0
3 years ago
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Another name for a pivot point is the:
Makovka662 [10]

Answer:

I think it's c .... fulcrum

7 0
3 years ago
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