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Artist 52 [7]
1 year ago
14

Name two laboratory equipment in the picture . b ) Identify two mistakes that these people in the laboratory above are doing​

Physics
1 answer:
pishuonlain [190]1 year ago
3 0

The two laboratory equipment in the picture are beaker and chemicals.The people in the picture are not wearing any protective gears while (a) working in the laboratory (b) Throwing the chemicals on the floor.

Among the many items that would be considered general lab equipment are pipettes, scales, centrifuges, Bunsen burners, freezers, hot plates, incubators, coolers, stirrers, water baths, and fume hoods

The dangers of working in a laboratory setting include:

Chemical hazards: Handling toxic substances can cause irritation and carcinogenicity.

Biological hazards: Biological hazards include hazards from working with small animals, working with blood borne pathogens and working with biological agents, such as viruses and bacteria.

Physical hazards: Physical hazards include exposure to noise, poor posture and the explosibility and flammability of substances.

Safety hazards: Safety hazards include unbalanced centrifuges, danger when handling hot sterilized items and electrical hazards, such as shock, explosions, blasts and electrocutions.

Allergy hazards: A common allergy hazard in the laboratory setting is a latex allergy, as many of the materials used in a laboratory setting are latex.

Learn more about Laboratory experiments at brainly.com/question/8430576

#SPJ9

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2.
larisa [96]

Answer:

Aceleración, a = 2 m/s²

Explanation:

Dados los siguientes datos;

Velocidad inicial = 108 km/h

Tiempo = 10 segundos

Velocidad final = 36 km/h

To find the average acceleration;

Conversión:

36 km/h to meters per seconds = 36*1000/3600 = 10 m/s

108 km/h to meters per seconds = 108*1000/3600 = 30 m/s

I. Para encontrar la aceleración, usaríamos la primera ecuación de movimiento;

V = U + at

Dónde;

V es la velocidad final.

U es la velocidad inicial.

a es la aceleración.

t es el tiempo medido en segundos.

Sustituyendo en la fórmula, tenemos;

30 = 10 + a*10

30 = 10 + 10a

10a = 30 - 10

10a = 20

Aceleracion = \frac{20}{10}

Aceleración, a = 2 m/s²

3 0
3 years ago
Calculate the speed of a bus that travels a distance of 55 miles in 0.75 hours.
Sonja [21]
Speed = distance / time = 55 / 0.75 = 73.3 miles per hour.
4 0
3 years ago
An object is projected straight upward with an initial speed of 25.0 m/s
hoa [83]

Answer:

What's the question your asking?

Explanation:

It moves with an initial speed of 25.0 miles per second.

4 0
3 years ago
A projectile is shot horizontally at 23.4 m/s from the roof of a building 55.0 m tall. What is the time necessary for the projec
baherus [9]
The horizontal speed has no effect on the answer. 

It doesn't matter whether you flick a marble horizontally from the roof,
fire a high-power rifle horizontally from the roof, drive a school bus straight
off the roof, or drop a bowling ball from the roof with zero horizontal speed. 
Their vertical speed is completely determined by gravity, (and it happens to
be the same for all of them).

Handy dandy formula for the distance covered by anything that starts out
with zero speed and accelerates to the end:

            Distance = (1/2) (acceleration) x (time)²

If the beginning of the journey is on Earth, then the acceleration is
9.8 m/s² ... the acceleration of gravity on Earth.  We'll assume that
the 55-meter rooftop in the question is part of a building on Earth.

                       55 meters  =  (1/2) (9.8 m/s²) x (time)²           

Divide each side
by  4.9 m/s² :            55 m / 4.9 m/s²  =  (time)²

                                 (time)²  =  (55/4.9)  sec²

Square-root
each side:                time  =  √(55/4.9 sec²)

                                           =      3.35 sec  .
5 0
3 years ago
Lindsay is planning a flight from St. Catharines to Hamilton, which lies due west of St. Catharines. Her aircraft flies at a spe
olga nikolaevna [1]

Lindsay has to fly this plane towards this direction [W 12.5° S] to get to Hamilton.

From this question, the plane is still up in the air.

We have wind blowing in [W 60° N ]

To solve the problem we have to make use of the sine rule

\frac{SinA}{a}=\frac{SinB}{b} =\frac{SinC}{c}

We put the values in the equation, we have:

50/Sinθ = 200/sin60°

The next step is to cross multiply

50 x sin60° = 200Sinθ

50 x 0.8660 = 200sinθ

We make Sin θ the subject

Sine θ = 43.30/200

sine θ = 0.2165

we find the value of θ

θ = sine⁻¹(0.2165)

θ = 12.50

So Lindsay has to fly this plane towards this direction

[W 12.5° S]

Here is a similar question brainly.com/question/13338067?referrer=searchResults

7 0
3 years ago
Read 2 more answers
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