What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?
2 answers:
The equation for force is force is equal to mass times acceleration or 
where:
- Force or F is measured in Newtons or N (which is also kilogram-meter per second squared),
- Mass or m is measured in kilograms or kg, and acceleration is measured in meters per second or m/s2.
This leads to an answer in kilogram-meter per second squared or kg- m/s2<span>So if we multiply a body with a mass of 15 kilograms to a rate of 8 meters per second, we get 120 kilogram-meter per second squared. </span>
- Force or F is measured in Newtons or N (which is also kilogram-meter per second squared),
- Mass or m is measured in kilograms or kg, and acceleration is measured in meters per second or m/s2.
This leads to an answer in kilogram-meter per second squared or kg- m/s2<span>So if we multiply a body with a mass of 15 kilograms to a rate of 8 meters per second, we get 120 kilogram-meter per second squared. </span>
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Answer:
The magnitude of the static frictional force is 1200 N
Explanation:
given information :
radius, r = 0.380 m
applied-torque, τ1 = 456 N
The car has a constant velocity, thus the acceleration is zero
α = 0
Στ = I α
τ1 - τ2 = I α
τ2 = counter-torque
τ1 - τ2 = 0
τ1 = τ2
r x = τ1
= the static frictional force (N)
= τ1 /r
= 456 N/0.380 m
= 1200 N
Responder:
35,2 ohm.
Explicación:
Dado:
La resistencia específica del conductor es,
La longitud del conductor es,
El área de la sección transversal del conductor es,
Sabemos que la resistencia de un conductor es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
Por lo tanto, la resistencia se puede expresar como:
Ahora, conecte los valores dados y resuelva para 'R'. Esto da,
Por lo tanto, la resistencia del conductor es de 35,2 ohm.
Here We can use principle of angular momentum conservation
Here as we know boy + projected mass system has no external torque
Since there is no torque so we can say the angular momentum is conserved
now we know that
m = 2 kg
v = 2.5 m/s
L = 0.35 m
I = 4.5 kg-m^2
now plug in all values in above equation
so the final angular speed will be 0.37 rad/s
The final kinetic energy of the ball is 2.45 J
Explanation:
We can solve this problem by using the law of conservation of energy.
In absence of frictional effect, the mechanical energy of the apple must be conserved during the fall. So we can write:
where :
is the initial potential energy, at the top
is the initial kinetic energy, at the top
is the final potential energy, at the bottom
is the final kinetic energy, at the bottom
By explicing the potential energy, we can rewrite the equation as:
where:
m = 0.5 kg is the mass of the apple
is the acceleration of gravity
is the initial height
is the final height
The initial kinetic energy is zero, since the ball starts from rest:
Therefore we can solve the equation for , the final kinetic energy of the ball:
Learn more about kinetic energy and potential energy:
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