What force is required to accelerate a body with a mass of 15 kilograms at a rate of 8 m/s²?
2 answers:
The equation for force is force is equal to mass times acceleration or 
where:
- Force or F is measured in Newtons or N (which is also kilogram-meter per second squared),
- Mass or m is measured in kilograms or kg, and acceleration is measured in meters per second or m/s2.
This leads to an answer in kilogram-meter per second squared or kg- m/s2<span>So if we multiply a body with a mass of 15 kilograms to a rate of 8 meters per second, we get 120 kilogram-meter per second squared. </span>
- Force or F is measured in Newtons or N (which is also kilogram-meter per second squared),
- Mass or m is measured in kilograms or kg, and acceleration is measured in meters per second or m/s2.
This leads to an answer in kilogram-meter per second squared or kg- m/s2<span>So if we multiply a body with a mass of 15 kilograms to a rate of 8 meters per second, we get 120 kilogram-meter per second squared. </span>
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Answer:
the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Explanation:
Given that;
weight of vehicle = 4000 lbs
we know that 1 kg = 2.20462
so
m = 4000 / 2.20462 = 1814.37 kg
Initial velocity = 60 mph = 26.8224 m/s
Final velocity = 30 mph = 13.4112 m/s
now we determine change in kinetic energy
Δk = m(
² -
² )
we substitute
Δk = ×1814.37( (26.8224)² - (13.4112)² )
Δk = × 1814.37 × 539.5808
Δk = 489500 Joules
we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule
so
Δk = 489500 / 3.6 × 10⁶
Δk = 0.13597 ≈ 0.136 kWh
Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh