Dashun Mack: Attempt
1 answer:
The time elapsed when the ball reaches the window is 1.55s
As per the question:
Final velocity, v = 11 m/s
Height, h = 29m
Acceleration, a = g = -9.8 m/s
From the third equation of motion:
v² = u² +2as
u² = v² - 2as
u² = (11)² - 2 × (-9.8) × (29)
u² = 689.4
u = √689.4
u = 26.25 m/s
Now, from the first equation of motion:
v = u + at
t = 1.55 s
Therefore, the time elapsed when the ball reaches the window is 1.55s.
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