Question

Dashun Mack: Attempt

Answer 1

The time elapsed when the ball reaches the window is 1.55s

As per the question:

Final velocity, v = 11 m/s

Height, h = 29m

Acceleration, a = g = -9.8 m/s

From the third equation of motion:

v² = u² +2as

u² = v² - 2as

u² = (11)² - 2 × (-9.8) × (29)

u² = 689.4

u = √689.4

u = 26.25 m/s

Now, from the first equation of motion:

v = u + at

$t=\frac{v-u}{-g}$

$t = \frac{11 -26.25}{-9.8}$

t = 1.55 s

Therefore, the time elapsed when the ball reaches the window is 1.55s.

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