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Margaret [11]
1 year ago
12

32. the width of the central peak in a single-slit diffraction pattern is 5.0 mm. the wavelength of the light is 600 nm, and the

screen is 2.0 m from the slit. (a) what is the width of the slit? (b) determine the ratio of the intensity at 4.5 mm from the center of the pattern to the intensity at the center.
Physics
1 answer:
Gnoma [55]1 year ago
8 0

The width of the slit is 0.192mm

In a single slit diffraction, the slit width is given as

d= mλD/y

​d= (1)(800mm)(600A)/ 2.5mm

d=(19.2×10^5 )10 ^−7mm

d=0.192mm.

The spreading out of waves as they pass through an aperture or around objects is referred to as diffraction. It happens when the aperture or obstacle is of the same order of magnitude as the incident wave's wavelength. The vast majority of the wave is blocked by very small aperture sizes.

To learn more about width of the slit see the link

brainly.com/question/14989294?referrer=searchResults

#SPJ4

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