Question

Napoleon’s cannon, having a muzzle velocity of 333 m/s, is fired at a 0 degree angle off a cliff. The ball lands 622 m away from the cannon. How far above ground level is the cannon?

Answer 1

The cannon is 17.69 m above the ground level

Data obtained from the question

The following data were obtained from the question:

• Horizontal speed (u) = 333 m/s
• Horizontal distance (s) = 622 m
• Height (h) =?

How to determine the time

We'll begin by calculating the time taken for the ball to land on the ground. This can be obtained as follow:

• Horizontal speed (u) = 333 m/s
• Horizontal distance (s) = 622 m
• Time (t) =?

s = ut

622 = 333 × t

Divide both sides by 333

t = 622 / 333

t = 1.9 s

How to determine the height

The height of the cannon above the ground can be obtained as illustrated below:

• Acceleration due to gravity (g) = 9.8 m/s²
• Time (t) = 1.9 s
• Height (h) =?

h = ½gt²

h = ½ × 9.8 × 1.9²

h = 4.9 × 3.62

h = 17.69 m

Learn more about motion under gravity:

brainly.com/question/20385439

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