The fixed point that a lever pivots around is the ?
2 answers:
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Answer:
v = 1.28 m/s
Explanation:
Given that,
Maximum compression of the spring,
Spring constant, k = 800 N/m
Mass of the block, m = 0.2 kg
To find,
The velocity of the block when it first reaches a height of 0.1 m above the ground on the ramp.
Solution,
When the block is bounced back up the ramp, the total energy of the system remains conserved. Let v is the velocity of the block such that,
Initial energy = Final energy
Substituting all the values in above equation,
v = 1.28 m/s
Therefore the velocity of block when it first reaches a height of 0.1 m above the ground on the ramp is 1.28 m/s.
The distance travelled during the given time can be found out by using the equations of motion.
The distance traveled during the time interval is "13810.8 m".
First, we will find the deceleration of the motorcycle by using the first <em>equation of motion</em>:
where,
vi = initial velocity = (518 km/h) = 143.89 m/s
vf = final veocity = 60 % of 143.89 m/s = (0.6)(143.89 m/s) = 86.33 m/s
a = deceleration = ?
t =time interval = 2 min = 120 s
Therefore,
a = -0.48 m/s²
Now, we will use the second <em>equation of motion </em>to find out the distance traveled (s):
<u>s = 13810.8 m = 13.81 km</u>
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Learn more about the equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion.
