Answer:
Na(OH)²
Explanation:
We look for the charges in the periodic table
Argon is perticularly important for the metal industry, being used as an inert gas shield in arc
1.00 degree increase<span> on the </span>Celsius scale<span> is </span>equivalent<span> to a </span>1.80 degree increase<span> on the</span>Fahrenheit scale<span>. If a </span>temperature increases<span> by </span>48.0°C<span>, </span>
Ba(NO₃)₂ + Na₂SO₄ → 2NaNO₃ + BaSO₄
The reaction goes to completion because it has the same amount of elements in the reactants and products.
Answer:
331 g
Explanation:
Step 1: Write the balanced equation
N₂(g) + 3 H₂(g) → 2 NH₃(g)
Step 2: Calculate the moles corresponding to 400 g of ammonia
The molar mass of ammonia is 17.03 g/mol.
![400g \times \frac{1mol}{17.03g} =23.5mol](https://tex.z-dn.net/?f=400g%20%5Ctimes%20%5Cfrac%7B1mol%7D%7B17.03g%7D%20%3D23.5mol)
Step 3: Calculate the moles required of nitrogen
The molar ratio of N₂ to NH₃ is 1:2.
![23.5molNH_3 \times \frac{1molN_2}{2molNH_3} =11.8molN_2](https://tex.z-dn.net/?f=23.5molNH_3%20%5Ctimes%20%5Cfrac%7B1molN_2%7D%7B2molNH_3%7D%20%3D11.8molN_2)
Step 4: Calculate the mass corresponding to 11.8 moles of nitrogen
The molar mass of nitrogen is 28.01 g/mol.
![11.8 mol \times \frac{28.01g}{mol} =331 g](https://tex.z-dn.net/?f=11.8%20mol%20%5Ctimes%20%5Cfrac%7B28.01g%7D%7Bmol%7D%20%3D331%20g)