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Snezhnost [94]
1 year ago
6

hergy A Sprinter runs at a a forward velocity of 10,9 m/s. If the sprinter has a mass of 72.5 kg, What is the Sprinter's Kinetic

energy? Answer!​
Physics
1 answer:
Nina [5.8K]1 year ago
7 0

Answer:

4306.8625 J or 344549/80J (fraction form)

Explanation:

kinetic energy= \frac{1}{2\\}mv²

= \frac{1}{2}×72.5×10.9²

= 4306.8625 J  or 344549/80 J

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URGENT!!!!!!!<br><br> PLEASE HELP WITH THIS PHYSICS PROBLEM
Levart [38]

Explanation:

Let

x_1 = distance traveled while accelerating

x_2 = distance traveled while decelerating

The distance traveled while accelerating is given by

x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2

\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2

\:\:\:\:\:= 1125\:\text{m}

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

v^2 = v_0^2 + 2ax_2

0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2

Solving for x_2, we get

x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}

\:\:\:\:\:= 4327\:\text{m}

Therefore, the total distance x is

x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}

\:\:\:\:= 5452\:\text{m}

3 0
3 years ago
You ride your bike for a distance of 30 km. You travel at a speed of 0.75 km/ minute. How many minutes does this take?
dolphi86 [110]
(30 km)/(0.75 km/min) = 40 min
4 0
3 years ago
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10.8 seconds is the correct answ

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high school physics, no need detail explain, just give the answer, but you have to make sure thank you
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The velocity at the midway point of a ball able to reach a height y when thrown with velocity vi at the origin is:
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Assuming the ball follows classical 2D projectile motion (moves in a parabola) and that the height y = the maximum height the ball goes in the y direction (because this would be its midpoint), then the velocity at height y is equal to the initial x component of velocity. At the midpoint, the y component is zero, so the velocity only depends on the x component. Projectiles move at constant speed in the x direction, so X = Xo. As long as you know actual values for Vi and either the initial angle or one initial component, then you can solve for Xo using trigonometry. Xo is thus the velocity of the ball once it has reached its maximum height. 
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