A charged object creates an electric field - an alteration of the space or field in the region that surrounds it. Other charges in that field would feel the unusual alteration of the space. Whether a charged object enters that space or not, the electric field exists.
Answer:
The answer to your question is π = 12.47 atm
Explanation:
Data
mass of Magnesium citrate = 25.5 g
volume of solution = 244 ml
temperature = 37°C
molar mass C₆H₆MgO₇ = (12 x 6) + (1 x 6) + (24 x 1) + (16 x 7) = 214 g
Osmotic pressure = π = ?
Process
1.- Calculate the moles of magnesium citrate
214 grams ----------------- 1 mol
25.5 grams --------------- x
x = (25.5 x 1)/214
x = 0.119
2.- Calculate molarity
Molarity = moles/volume
Molarity = 0.119/0.244
Molarity = 0.49
3.- Calculate osmotic pressure
π = MRT
π = (0.49)(0.0821)(37 + 273)
π = (0.49)(0.0821)(310)
π = 12.47 atm
Answer:
Density stays the same
Explanation:
The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
Answer:
1 and 2
Explanation:
The given equation is:
Cl₂ + H₂ → 2HCl
A coefficient is the variable or number before a chemical specie.
In this reaction Cl₂ and H₂ are the reactants;
The coefficient of Cl₂ is 1,
H₂ is 1,
HCl is 2
The subscript is the number to the lower power after a chemical specie is denoted.
For Cl₂, it is 2
Answer:
E - Be and O
A - Mg and N
E - Li and Br
F - Ba and Cl
B - Rb and O
Explanation:
Be and O
Be is a metal that loses 2 e⁻ to form Be²⁺ and O is a nonmetal that gains 2 e⁻ to form O²⁻. For the ionic compound to be neutral, it must have the form BeO (E-MX).
Mg and N
Mg is a metal that loses 2 e⁻ to form Mg²⁺ and N is a nonmetal that gains 3 e⁻ to form O³⁻. For the ionic compound to be neutral, it must have the form Mg₃N₂ (A-M₃X₂).
Li and Br
Li is a metal that loses 1 e⁻ to form Li⁺ and Br is a nonmetal that gains 1 e⁻ to form Br⁻. For the ionic compound to be neutral, it must have the form LiBr (E-MX).
Ba and Cl
Ba is a metal that loses 2 e⁻ to form Ba²⁺ and Cl is a nonmetal that gains 1 e⁻ to form Cl⁻. For the ionic compound to be neutral, it must have the form BaCl₂ (F-MX₂).
Rb and O
Rb is a metal that loses 1 e⁻ to form Rb⁺ and O is a nonmetal that gains 2 e⁻ to form O²⁻. For the ionic compound to be neutral, it must have the form Rb₂O (B-M₂X).
