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sveticcg [70]
3 years ago
7

What is the purpose of a branch circuit in your home?

Physics
2 answers:
leva [86]3 years ago
7 0

Answer:

A branch circuit is the circuit conductor between the final overcurrent device protecting the circuit and the outlet(s). Branch circuits are divided into four categories: appliance, general purpose, individual and multiwire

Explanation:

Leona [35]3 years ago
6 0

Answer:it is the conductor for all the other circuits.

Explanation:One circuit runs off an conductor multiple circuits runoff a branch

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A student drops a rock from a bridge to the water 12m below. How many seconds does it take the rock to hit the water?
ANEK [815]
R = \frac{g t^{2} }{2}
r - displacement or height
t - time taken
g = 10 m/s-2
t = square root from 2r/g = \sqrt{ \frac{2 x 12}{10} } = 1.5 seconds
7 0
3 years ago
Mike Powell holds the record for the long jump of 8.95 m, established in 1991. If he left the ground at an angle of 18.8°, what
maksim [4K]

Answer:

<em>12 m/s</em>

Explanation:

<u>Projectile Motion</u>

It's also known as 2D motion because the movement takes place in both axis x and y. The x-axis motion is at a constant speed since in absence of friction, no external force stops or accelerates the object. The y-axis motion is at variable speed, which is changed by the acceleration of gravity that makes the object to reach a maximum height and then go back to ground level.

The maximum horizontal distance reached (also called Range) is given by

\displaystyle X_m=\frac{V_{o}^2sin2\theta}{g}

Knowing that \theta=18.8^o, X_m=8.95\ m, we solve for Vo

\displaystyle V_o=\sqrt{\frac{gX_m}{sin2\theta}}

\displaystyle V_o=\sqrt{\frac{9.8\cdot 8.95}{sin(2\cdot 18.8^o)}}=12\ m/s

Thus, the initial speed of Mike Powell was 12 m/s

7 0
3 years ago
In 1865, jules verne proposed sending men to the moon by firing a space capsule from a 220-m-long cannon with final speed of 10.
Aneli [31]
I'm going to assume that the 10.97 km/s is the velocity at the end of the cannon.

vi = 0
d = 220m
vf = 10.97 km/s = 10970 m/s
a = ???

vf^2 = vi^2 + 2*a*d
10970^2 = 0 + 2*a*220
10970^2 / 440 = a You are right this is a pretty big number.
2.73 * 10^5 = a


5 0
3 years ago
A car starts from rest and accelerates uniformly over a time of 18 seconds for a distance of 390 m. Determine the acceleration o
Sergeeva-Olga [200]

Answer:

a=2.4\ m/s^2

Explanation:

Given that,

The initial speed of a car, u = 0

Time, t = 18 s

Distance, d = 390 m

We need to find the acceleration of the car. Let it is a. Using the second equation of motion to find it.

d=ut+\dfrac{1}{2}at^2

or

d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 390}{(18)^2}\\\\a=2.4\ m/s^2

So, the acceleration of the car is 2.4\ m/s^2.

5 0
3 years ago
The diagram shows a person using a piece of gym equipment to lift weights.
ki77a [65]

Answer:

C. The lower legs are levers, and the knees are fulcrums. The ankles hold the loads.

Explanation:

3 0
4 years ago
Read 2 more answers
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