R =

r - displacement or height
t - time taken
g = 10 m/s-2
t = square root from 2r/g =

= 1.5 seconds
Answer:
<em>12 m/s</em>
Explanation:
<u>Projectile Motion</u>
It's also known as 2D motion because the movement takes place in both axis x and y. The x-axis motion is at a constant speed since in absence of friction, no external force stops or accelerates the object. The y-axis motion is at variable speed, which is changed by the acceleration of gravity that makes the object to reach a maximum height and then go back to ground level.
The maximum horizontal distance reached (also called Range) is given by

Knowing that
, we solve for Vo


Thus, the initial speed of Mike Powell was 12 m/s
I'm going to assume that the 10.97 km/s is the velocity at the end of the cannon.
vi = 0
d = 220m
vf = 10.97 km/s = 10970 m/s
a = ???
vf^2 = vi^2 + 2*a*d
10970^2 = 0 + 2*a*220
10970^2 / 440 = a You are right this is a pretty big number.
2.73 * 10^5 = a
Answer:

Explanation:
Given that,
The initial speed of a car, u = 0
Time, t = 18 s
Distance, d = 390 m
We need to find the acceleration of the car. Let it is a. Using the second equation of motion to find it.

or

So, the acceleration of the car is
.
Answer:
C. The lower legs are levers, and the knees are fulcrums. The ankles hold the loads.
Explanation: