Question

Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :______

Answer 1

Answer:

3980.89 ohms

Explanation:

The capacitive reactance is expressed as;

$X_c = \frac{1}{2 \pi fC}$

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = $40 * 10^{-6}F$

Substitute into the formula:

$X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89$

Hence the  total capacitive reactance is 3980.89 ohms