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ohaa [14]
3 years ago
13

Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_

_____
Physics
1 answer:
Stells [14]3 years ago
5 0

Answer:

<em> 3980.89 ohms</em>

Explanation:

The capacitive reactance is expressed as;

X_c = \frac{1}{2 \pi fC}

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = 40 * 10^{-6}F

Substitute into the formula:

X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c =  \frac{1}{0.0002512}\\X_c = 3,980.89

<em>Hence the  total capacitive reactance is 3980.89 ohms</em>

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1. 168.1 Hz

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The equation representing Young's Modulus is:

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