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ohaa [14]
3 years ago
13

Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_

_____
Physics
1 answer:
Stells [14]3 years ago
5 0

Answer:

<em> 3980.89 ohms</em>

Explanation:

The capacitive reactance is expressed as;

X_c = \frac{1}{2 \pi fC}

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = 40 * 10^{-6}F

Substitute into the formula:

X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c =  \frac{1}{0.0002512}\\X_c = 3,980.89

<em>Hence the  total capacitive reactance is 3980.89 ohms</em>

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we can find how far the second drop was when the first drop hits the ground from the formula s = ut + 0.5at^{2}

where

  • s = distance
  • u = initial velocity = 0
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(B) When the first drop strikes the floor, how far below the nozzle is the third drop.

we can find how far the third drop was when the first drop hits the ground from the formula s = ut + 0.5at^{2}

where

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  • u = initial velocity = 0
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substituting all required values we have

s = 0 + (0.5 x 9.8 x (\frac{1}{3}T)^{2})

s = 0 + (0.5 x 9.8 x (\frac{1}{3} x 6.4)^{2})

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