Answer:
a. .250 moles
Explanation:
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In this case, since we can see how the hydrogen is given off as a product of the reaction and we can model its behavior via the ideal gas equation, it is possible for us to use such equation for the determination of the collected moles:
Next, since the STP conditions account for a pressure of 1 atm and a temperature of 273 K, the moles turn out to be:
Thus the answer is a. .250 moles
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Answer:
6.)
7.) 134.4 g O₂
Explanation:
The unbalanced equation:
NH₃ (g) + O₂ (g) ---> N₂ (g) + H₂O (g) + energy
<u>Reactants</u>: 1 nitrogen, 3 hydrogen, 2 oxygen
<u>Products</u>: 2 nitrogen, 2 hydrogen, 1 oxygen
The balanced equation:
4 NH₃ (g) + 3 O₂ (g) ---> 2 N₂ (g) + 6 H₂O (g) + energy
<u>Reactants</u>: 4 nitrogen, 12 hydrogen, 6 oxygen
<u>Products</u>: 4 nitrogen, 12 hydrogen, 6 oxygen
To convert from moles to grams, you need to multiply the starting value (4.2 moles) by the molar mass (32.00 g/mol). The molar mass can serve as a conversion because it technically means there are 32.00 grams O₂ per every 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (the desired unit should be in the numerator).
4.2 moles O₂ 32.00 g
-------------------- x ---------------- = 134.4 g O₂
1 mole
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