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Bess [88]
3 years ago
10

The reaction for the burning of one type of match tip is as follows: P4S3(s) + 8 O2(g) P4O10(g) + 3 SO2(g) What volume of SO2 at

STP can be produced by burning 1.00 g P4S3 in excess O2?
Chemistry
1 answer:
miskamm [114]3 years ago
4 0

a] work out mass of 1 mole P4S3 -- call this Y grams

b] eqtn tells you 1 mole P4S3 gives 3 moles SO2 [= 3 x 22.4L at STP]  

c] by simple proportion  

1g P4S3 gives (3 x 22.4)/Y SO2 at STP answer

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Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
2 years ago
Using the redox reaction below determine which element is oxidized and which is reduced. 4nh3 + 3ca(clo)2 → 2n2 + 6h2o + 3cacl2
lys-0071 [83]
The oxidation number of elements in equation below are,

                         4NH₃ + 3Ca(ClO)₂ → 2N₂ + 6H₂O + 3CaCl₂

O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
O.N of N in N₂ = 0
O.N of Cl in Ca(ClO)₂ = +1
O.N of Cl in CaCl₂ = -1

Oxidation:
               Oxidation number of Nitrogen is increasing from -3 (NH₃) to 0 (N₂).

Reduction:
               Oxidation number of Cl is decreasing from +1 [Ca(ClO)₂] to -1 (CaCl₂).

Result:
          <span>N is oxidized and Cl is reduced.</span>
6 0
3 years ago
Read 2 more answers
I need help can you help
telo118 [61]
I can sure try to help!
8 0
2 years ago
Steel is the most commonly used metallic material. However, its annual loss due to corrosion is huge. Preventing metal corrosion
Fiesta28 [93]

Answer:

d

Explanation:

elvis's do fhgffgcgxcycy

5 0
2 years ago
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A great white shark has resided at a depth where the pressure is 16 atm. If the initial volume of its swim bladder is 4 L, what
padilas [110]

Answer:

The new volume of the gas is 32L

Explanation:

P1 = 16atm

V1 = 4L

P2 = atm

V2 = ?

According to Boyle's law, the volume of a given mass of gas is inversely proportional to its volume provided the temperature remains constant.

P1 * V1 = P2 * V2

V2 = (P1 * V1) / P2

V2 = (16 * 4) / 2

V2 = 64 / 2

V2 = 32L

The new volume of the gas is 32L

6 0
3 years ago
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