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Bess [88]
3 years ago
10

The reaction for the burning of one type of match tip is as follows: P4S3(s) + 8 O2(g) P4O10(g) + 3 SO2(g) What volume of SO2 at

STP can be produced by burning 1.00 g P4S3 in excess O2?
Chemistry
1 answer:
miskamm [114]3 years ago
4 0

a] work out mass of 1 mole P4S3 -- call this Y grams

b] eqtn tells you 1 mole P4S3 gives 3 moles SO2 [= 3 x 22.4L at STP]  

c] by simple proportion  

1g P4S3 gives (3 x 22.4)/Y SO2 at STP answer

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Answer:

The answers to the questions are given below.

Explanation:

According to Le Chatelier's principle, if an external constrain such as change in concentration, temperature or pressure is imposed on a chemical system in equilibrium, the equilibrium will shift in order to neutralize the effect.

A. Effective of removing ammonia, NH3.

N2(g) + 3H2(g) ⇌ 2NH3(g)

Removing NH3 from the reaction simply means we are left with more reactants and no product. Therefore, the reactant will react to produce the product. Hence, the equilibrium position will shift to the right.

2. Effect of removing H2

N2(g) + 3H2(g) ⇌ 2NH3(g)

Remoing H2 simply means we have more products and less reactant. Therefore, the product will be convert to reactant. Hence, the equilibrium position will shift to the left.

C. Effect of adding a catalyst.

N2(g) + 3H2(g) ⇌ 2NH3(g)

Catalyst does not affect the equilibrium position. It only creates an alternative path to arrive at the product within a short time. Hence, it has no effect.

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3 years ago
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kiruha [24]

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Answer:

A = 2

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