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DENIUS [597]
1 year ago
13

Nh4cl is sometimes preferred instead of hcl or h2so4 for "acid" work-up after grignard reactions, particularly when the expected

and desired product is a tertiary alcohol. Why?
Chemistry
1 answer:
Free_Kalibri [48]1 year ago
6 0

Nh4cl is sometimes preferred instead of hcl or h2so4 for "acid" work-up after grignard reactions, particularly when the expected and desired product is a tertiary alcohol because NH4+ is a much milder acid than HCl or H2SO4, which achieve the protonation of

the oxyanion to yield the alcohol while minimizing the risk of dehydration.

Ammonium chloride (NH4Cl) is the used as reagent that quenches the magnesium alkoxide product of the Grignard addition.

It is a proton source without being acidic as in acidic medium the protonation of the tertiary alcohol product and elimination to the alkene.

In the presence of HCl or any other strong acid protonation proceed and form alkene but not with ammonium chloride.

Thus from above we concluded that Nh4cl is preferred instead of hcl or h2so4 for "acid" work-up after grignard reactions.

learn more about grignard reagent:

brainly.com/question/15876201

#SPJ4

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7 0
3 years ago
PLEASE HELP ME WITH THIS QUESTION!!!!
elena-s [515]
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5 0
3 years ago
Read 2 more answers
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insens350 [35]
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6 0
3 years ago
Neon gas has a volume of 261 ml and a pressure of 108.5 kPa. What volume will the gas occupy at 96.5 kPa if the temperature rema
Tatiana [17]

Answer:

\large \boxed{\text{293 mL}}

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{108.5 kPa}\qquad & V_{1} &= & \text{261 mL} \\p_{2}& =& \text{96.5 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:  

\begin{array}{rcl}108.5 \times 261 & =& 96.5V_{2}\\28320 & = & 96.5V_{2}\\V_{2} & = &\dfrac{28320}{96.5}\\\\& = &\textbf{293 mL}\\\end{array}\\\text{The volume of the gas is } \large \boxed{\textbf{293 mL}}

5 0
3 years ago
A 30.00 mL sample of HBr was titrated using 0.1756 M NaOH. Determine the concentration of the HBr sample if 17.52 mL of NaOH was
postnew [5]

<u>Answer:</u> The concentration of HBr sample is 0.1025 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HBr

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=30.00mL\\n_2=1\\M_2=0.1756M\\V_2=17.52mL

Putting values in above equation, we get:

1\times M_1\times 30.00=1\times 0.1756\times 17.52\\\\M_1=\frac{1\times 0.1756\times 17.52}{1\times 30.00}=0.1025M

Hence, the concentration of HBr sample is 0.1025 M

5 0
3 years ago
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