Lol i think i had the same worksheet!! lol anyway look up newtons first law and it will be pretty self explanatory from there
Answer:
E = 1/2 m v^2 = 1/2 k x^2 equating KE of coyote and spring
x^2 = m v^2 / k = 10 kg * 20^2 m^2 / s^2 / 400 N / m
x^2 = 10 * 400 / 400 (kg m^3 / kg-m) = 10 m^2
x = 3.16 m
Answer: 40m/s
Explanation:
Given that,
speed of car (v) = ?
Mass of car (m) = 500.0 kilogram
Kinetic energy (KE) = 400,000 joules
Recall that kinetic energy is possessed by a moving object, and it depends on the mass and speed by which the object moves
i.e Kinetic energy = 1/2mv²
400,000J = 1/2 x 500.0kg x v²
400,000J = 250.0kg x v²
v² = 400,000J / 250.0kg
v² = 1600
Find the square root of v²
v = √1600
v = 40m/s
Thus, the speed of the car is 40m/s
Answer:
The vapour pressure of water is great tah 50 than it is 10.
Answer:
The velocity at the top will be 26.4522 m/sec
Explanation:
We have given
The diameter of the loop d = 48.01 m
Radius of the loop 
The apparent weight at the top is given by 
As the in question it is given that apparent weight is equal to 1.80 times of the real weight



So the velocity at the top will be 26.4522 m/sec