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Maksim231197 [3]
3 years ago
13

From the last problem, what is the ratio of the ppm change in CO2 to the ppm change in CH4? Assume that the concentrations of CO

2 and CH4 start at their present-day values of 400 ppm and 1.7 ppm, respectively.
Physics
1 answer:
xxMikexx [17]3 years ago
3 0

An additional 10ppm of methane will change the upward IR heat flux (in tropical

atmosphere) from 289.29 W/m2

to 286.211 W/m2

, which is a reduction of 3.08

W/m2

.

An additional 10ppm of CO2 will change the upward IR heat flux from 289.29 W/m2

to 289.29 W/m2

, which is a change of 0.13 W/m2

.

Therefore, an additional 10 ppm of methane would have a much larger impact on

the outgoing infrared flux than an additional 10 ppm of CO2 at current

concentrations

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cupoosta [38]

Answer:

Read below!

Explanation:

You can watch the sun wheel across the sky during the day, and the stars at night. Focus a telescope on any star besides the north star--especially southern stars--and you can watch them drift across your field of view.  

An alternative explanation is that all the stars are painted on (or holes in) some canopy that rotates around the earth. This explanation does not account for the motion of the "wanderers," or planets, as the Greeks called them, or for the path of the moon among the stars.  

As we know the stars are massive bodies of significant and varying distance to the earth, the notion they all swing around us in unison seems highly implausible

4 0
3 years ago
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The last one, the soil will become weak & unable to support plant growth
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A third baseman makes a throw to first base 40.5 m away. The ball leaves his hand with a speed of 30.0 m/s at a height of 1.4 m
Ugo [173]

Answer:

When the ball goes to first base it will be 4.23 m high.

Explanation:

Horizontal velocity = 30 cos17.3 = 28.64 m/s

   Horizontal displacement = 40.5 m

   Time  

         t=\frac{40.5}{28.64}=1.41s          

   Time to reach the goal posts 40.5 m away = 1.41 seconds

Vertical velocity = 30 sin17.3 = 8.92 m/s

    Time to reach the goal posts 40.5 m away = 1.41 seconds

    Acceleration = -9.81m/s²

    Substituting in s = ut + 0.5at²

             s = 8.92 x 1.41 - 0.5 x 9.81 x 1.41²= 2.83 m

    Height of throw = 1.4 m

    Height traveled by ball = 2.83 m

    Total height = 2.83 + 1.4 = 4.23 m

    When the ball goes to first base it will be 4.23 m high.

8 0
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Convert 75°C into (A) kelvin (B) °F​
sukhopar [10]

Answer:

348.15K

Explanation:

75C+273.15=348.15K

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Sal sprinted 40 m to the right in 5.5s what is his average velocity
PolarNik [594]

Answer: 7.27 m/s

Explanation:

6 0
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