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stepan [7]
1 year ago
5

What is the molarity of a solution prepared by dissolving 36. 0 g of naoh in enough water to make 1. 50 l of solution?

Chemistry
1 answer:
Vlada [557]1 year ago
4 0

0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.

The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.

Amount of NaOH = 36. 0 g

Amount of water = 1. 50 L

1 mol of NaOH = 40 g,

Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.9 / 1.50

Molarity of a solution = 0.6 mol / L

To  know more about Molarity refer to:  brainly.com/question/8732513

#SPJ4

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CaO + H2O -> Ca(OH)2
yawa3891 [41]

The % yield of Ca(OH)₂ : 62.98%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

CaO + H₂O ⇒ Ca(OH)₂

mass CaO= 4.2 g

mol CaO(MW=56,0774 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{4.2}{56,0774 g/mol}\\\\mol=0.075

mol Ca(OH)₂ based on mol CaO

mol ratio CaO : Ca(OH)₂,= 1 : 1, so mol Ca(OH)₂ = 0.075

mass Ca(OH)₂(MW=74,093 g/mol) ⇒ theoretical

\tt mass=mol\times MW\\\\mass=0.075\times 74,093 g/mol\\\\mass=5.557~g

% yield :

\tt =\dfrac{actual}{theoretical}\times 100\%\\\\=\dfrac{3.5}{5.557}\times 100\%\\\\=62.98\%

8 0
2 years ago
As the vibration of molecules increases, the _____ of the substance increases.
garik1379 [7]
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3 years ago
HELPPP!!! In reaction 2Sr+O2=2SrO how many moles of Oxygen will be needed to react with 36.9g of SrO?
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What is the minimum cation-to-anion radius ratio (rC/rA) for an octahedral interstitial lattice site?
mash [69]

Answer:

0. 414

Explanation:

Octahedral interstitial lattice sites.

Octahedral interstitial lattice sites are in a plane parallel to the base plane between two compact planes and project to the center of an elementary triangle of the base plane.

The octahedral sites are located halfway between the two planes. They are vertical to the locations of the spheres of a possible plane. There are, therefore, as many octahedral sites as there are atoms in a compact network.

The Octahedral interstitial void ratio range is 0.414 to 0.732. Thus, the minimum cation-to-anion radius ratio for an octahedral interstitial lattice site is 0. 414.

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3 years ago
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