All categories

2 years ago

A 1200 kg sports car accelerates from 0 m/s to 30 m/s in 10 s. What is the average power of the engine?

Physics

2 answers:

DIA [1.3K]2 years ago

5 0

Answer:

3600N

Explanation:

Given: m = 1200kg, Vo = 0m/s, Vf = 30m/s, Δt = 10s

ΣF = ma

we need to find 'a' first, using the definition of 'a' we get equation:

a = (Vf-Vo)/Δt

a = (30m/s)/10s

a = 3 m/s^2

now substitute into top equation

ΣF = ma

Fengine = (1200kg)(3m/s^2)

Fengine = 3600N

trapecia [35]2 years ago

3 0

Answer:

P = 54000 W or P = 54 kW

Explanation:

P = Work/time

W = Force * distance

first, find acceleration to find net force using kinematics.

v = vo + at

30 = 0 + a(10)

a = 3 m/s^2

Fnet = ma = 1200(3) = 3600N = Force

Next, find the distance traveled using kinematics.

∆x = vo(t) + 1/2at^2

∆x = 0(10) + 1/2(3)10^2

∆x = 150 m

Now use the force and distance you just calculated to find the work done.

W = Force*distance

W = 3600N * 150m

W = 540000

Calculate power.

P = W/t

P = 540000/10

P = 54000 W

P = 54 kW

You might be interested in

Suppose a star the size of our Sun, but of mass 9.0 times as great, were rotating at a speed of 1.0 revolution every 17 days. If

Tanya [424]

Use the conservation of angular momentum; angular momentum at the beginning = angular momentum at the end
Conservation of angular momentum:
I1 w1 = I2 w2
Where I is the moment of inertia. For a sphere, I=2/5 m R^2. Substituting into the equation above we get
w2 = I1 w1 / I2 = w1 m1 R1^2 / (m2 R2^2)
w2 = w1 4 * (R1/R2)^2
= 4*(1)*(7E5/7.5)^2
= 3.48E10 revs/(17days)
= 2.04705882 x 10^9 revs/sec

4 0

3 years ago

A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant planet. If 20 complete oscillation are

givi [52]

Answer :

Explanation :

It is given that,

length of pendulum, l = 0.6 m

Number of oscillation, n = 20

time, t = 35.5 seconds

so, Time period, $T=\dfrac{t}{n}$

$T=\dfrac{35.5s}{20}$

we know that the time period of pendulum is given by

$T=2\pi\sqrt{\dfrac{l}{g}}$

$g=\dfrac{4\pi^2l}{T^2}$

$g=\dfrac{4\times(3.14)^2\times 0.6 \times (20)^2}{(35.5s)^2}$

$g=7.51\ m/s^2$

$g=7.52\ m/s^2$

6 0

3 years ago

Does an odometer in a car measure distance or displacement?

kifflom [539]

The odometer measures distance

5 0

3 years ago

Read 2 more answers

3. A large crane lifts a 25,000 kg mass in the air. The amount of work that must be done by the

andreev551 [17]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

5 0

3 years ago

The paths of the alpha particles depend on the forces on them in the metal.

grandymaker [24]

Answer:

During the experiment, alpha particles bombarded a thin piece of gold foil. The alpha particles were expected to pass easily through the gold foil. ... The discovery of the nucleus was a result of Rutherford's observation that a small percentage of the positively charged particles bombarding the metal's surface...

Explanation:

jayfeather friend me

6 0

3 years ago