Question

The potential difference between A and B is 5.0 V. A proton starts from rest at A. When it reaches B what is its kinetic energy? (e = 1.60 x 10^-19 C)

Answer 1

Answer:

total kinetic energy is 8 × $10^{-19}$ J

Explanation:

given data

potential difference = 5 V

e = 1.60 × $10^{-19}$ C

to find out

what is kinetic energy

solution

we will apply here conservation of energy that is

change in potential energy is equal to change in kinetic energy

so

change potential energy is e × potential difference

change potential energy =  1.60 × $10^{-19}$ × 5

change potential energy = 8 × $10^{-19}$ J

so change in kinetic energy  = 8 × $10^{-19}$ J

and we know proton start from rest that mean ( kinetic energy is 0 ) so

change in KE is total KE

total kinetic energy is 8 × $10^{-19}$ J